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Dafna11 [192]
2 years ago
3

Which expression is equivalent to StartRoot 120 x EndRoot? 2 StartRoot 30 x EndRoot 2 StartRoot 30 EndRoot 4 StartRoot 30 x EndR

oot 60 StartRoot 2 x EndRoot
Mathematics
1 answer:
julsineya [31]2 years ago
7 0

equivalent expression of StartRoot 120 x EndRoot is 2 StartRoot 30 x EndRoot

Option A is correct.

Step-by-step explanation:

We need to find equivalent expression of StartRoot 120 x EndRoot

Solving:

Converting into mathematical form.

\sqrt{120x}

Finding prime factors of 120

120: 2x2x2x3x5 = 2^2x2x3x5

Putting 2^2x2^2x3x5 instead of 120

=\sqrt{2^2\times 2\times 3\times 5\times x}\\We \,\,know\,\,\sqrt{2^2}=2\,\,so\\=2\sqrt{2\times 3\times 5\times x}\\=2\sqrt{30 x}

Solving \sqrt{120x} we get 2\sqrt{30 x}

So, equivalent expression of StartRoot 120 x EndRoot is 2 StartRoot 30 x EndRoot

Option A is correct.

Keywords: Solving radical expressions

Learn more about Solving radical expressions at:

  • brainly.com/question/7153188
  • brainly.com/question/10534381

#learnwithBrainly

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A poll stated that 32% of those polled think the economy is getting worse. An economist wanted to check this claim so she survey
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Answer:

z=\frac{0.30 -0.32}{\sqrt{\frac{0.32(1-0.32)}{750}}}=-1.174  

The p value for this case would be given by:

p_v =2*P(z  

For this case since the p value is higher than the significance level given we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true proportion is not significantly different from 0.32 or 32 %

Step-by-step explanation:

Information given

n=750 represent the random sample taken

\hat p=0.30 estimated proportion of  people who  thought the economy is getting worse

p_o=0.32 is the value that we want to verify

\alpha=0.05 represent the significance level

z would represent the statistic

p_v represent the p value

Hypothesis to test

We want to check if the true proportion of interest is equal to 0.32 or not.:  

Null hypothesis:p=0.32  

Alternative hypothesis:p \neq 0.32  

The statistic would be given by:

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

Replacing we got:

z=\frac{0.30 -0.32}{\sqrt{\frac{0.32(1-0.32)}{750}}}=-1.174  

The p value for this case would be given by:

p_v =2*P(z  

For this case since the p value is higher than the significance level given we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true proportion is not significantly different from 0.32 or 32 %

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2 years ago
5x680 in the Distributive property
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It is (5x600)+(5x80)=3400
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2 years ago
Let f(x)=34x2−1. The function g(x) is a vertical stretch of f(x) by a factor of 8. What is the equation of g(x)? Enter your answ
bezimeni [28]
For finding the answer of such a question, we only multiply the function by the given value. so as for f(x)=34x2−1, The function g(x), a vertical stretch of f(x) by a factor of 8 is g(x) =8(34x2−1)
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2 years ago
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Ramesh examined the pattern in the table. Powers of 7 Value 2,401 343 49 7 1 Ramesh says that based on the pattern . Which state
earnstyle [38]

1) You included neihter what Ramesh says nor the statements, then I can you tell some facts about the pattern.


2) The sequence is: 2401, 343, 49, 7, and 1.


3) The first term is 2401


4) The sequence is a decreasing geometric one.


5) The ratio is found dividing two consecutive terms (the second by the first, or the third by the second, or the fourth by the third, or the fifth by fourth):


1/7 = 7 / 49 = 49 / 343 = 343 / 2401.


So, the ratio is 1/7


6) The sum of that sequence is 2401 + 343 + 49 + 7 + 1 = 2801



7 0
2 years ago
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The state education commission wants to estimate the fraction of tenth grade students that have reading skills at or below the e
kow [346]

Answer:

The 80% confidence interval for the population proportion of tenth graders reading at or below the eighth grade level is (0.149, 0.207).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

Suppose a sample of 292 tenth graders is drawn. Of the students sampled, 240 read above the eighth grade level.

So 292 - 240 = 52 read below or at eight grade level, and that n = 292, \pi = \frac{52}{292} = 0.178

80% confidence level

So \alpha = 0.2, z is the value of Z that has a pvalue of 1 - \frac{0.2}{2} = 0.9, so Z = 1.28.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.178 - 1.28\sqrt{\frac{0.178*0.822}{292}} = 0.149

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.178 + 1.28\sqrt{\frac{0.178*0.822}{292}} = 0.207

The 80% confidence interval for the population proportion of tenth graders reading at or below the eighth grade level is (0.149, 0.207).

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