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vampirchik [111]

2 years ago

11

Corey, whose mass is 95 kg, stands on a bathroom scale in an elevator. The scale reads 850 N for the first 3.0 s after the eleva

tor starts to move, then 930 N for the next 3.0 s.What is the elevator's velocity 4.0 s after starting?

1 answer:

lyudmila [28]2 years ago

7 0

Answer:

v₂ = 2.568 m/s

Explanation:

given,

mass of Corey = 95 Kg

reading of sale for first 3 s when elevator start to move = 850 N

scale reading for the next 3.0 s = 930 N

Gravitation force acting =

F = m g

F = 95 x 9.8

F = 931 N

using newtons second law, due to movement of elevator

F_{net} = m a

W - N = m a₁

931- 850 = 95 x a₁

a₁ = 0.852 m/s²

now,

velocity calculation

v₁ = a₁t

v₁ = 0.852 x 3 = 2.557 m/s

now, For second case

931 - 930 = 95 x a₂

a₂ = 0.011 m/s²

now, velocity after 4 s

v₂ = v₁ + a₂ t

v₂ = 2.557+ 0.011 x (4 - 3)

(4-3) because velocity after 3 second is calculate we need to calculate velocity after 4 s from beginning.

v₂ = 2.557 + 0.011

v₂ = 2.568 m/s

velocity of the elevator is equal to v₂ = 2.568 m/s

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#1

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#2

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(iii) Buoyant force = 11.11 N

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#3

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