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Yuri [45]
2 years ago
8

According to the first rule, if a force pulls on one end of a rope, the tension in the rope equals the magnitude of the pulling

force. What is the magnitude T1 of the tension in rope 1?

Physics
2 answers:
Verdich [7]2 years ago
7 0

Answer:

Explanation:

If we pull the rope by a force F1 then the tension in the rope is same as that of F1.

T1 = F1 .

This forms an action reaction pair.

mixer [17]2 years ago
5 0

Answer:

F.

Explanation:

Here in the question the mass of the pulley is zero, hence, the tension in the cable throughout is same.

magnitude of tension in rope 1 is

T1= F

Hence the tension T1 is rope 1 is F.

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A 2.5-L tank initially is empty, and we want to fill it with 10 g of ammonia. The ammonia comes from a line with saturated vapor
Alex17521 [72]

Answer:

592.92 x 10³ Pa

Explanation:

Mole of ammonia required = 10 g / 17 =0 .588 moles

We shall have to find pressure of .588 moles of ammonia at 30 degree having volume of 2.5 x 10⁻³ m³. We can calculate it as follows .

From the relation

PV = nRT

P x 2.5 x 10⁻³ =  .588 x 8.32 x ( 273 + 30 )

P = 592.92 x 10³ Pa

3 0
2 years ago
The air in tires can support a car because gases __________.
____ [38]
Because the air inside the tires is kept at high pressure.

In fact, the force applied by the tires upwards to counter-balance the weight of the car (pushing downwards) is 
F=pA
where p is the pressure of the air inside the tires and A is the area of contact between the tire and the car. Therefore, a higher pressure means a larger force F, and eventually if the pressure p is higher enough the force F will be large enough to counterbalance the weight of the car.
8 0
2 years ago
One end of a piano wire is wrapped around a cylindrical tuning peg and the other end is fixed in place. The tuning peg is turned
liq [111]

Answer:

T = 3183 N

Explanation:

When the screw is turned by two turns then change in the length of the wire is given as

\Delta L = 2(2\pi r)

\Delta L = 4\pi r

\Delta L = 4(\pi)(1.0 mm)

\Delta L = 12.56 mm

now we know by the formula of Young's modulus

Y = \frac{T/A}{\Delta L/L}

so we have

T = \frac{AY \Delta L}{L}

T = \frac{\pi (0.55 \times 10^{-3})^2(2.0 \times 10^{11})(12.56 \times 10^{-3})}{0.75}

T = 3183 N

3 0
2 years ago
A solid uniform disk of diameter 3.20 m and mass 42 kg rolls without slipping to the ) bottom of a hill, starting from rest. If
Semenov [28]

Answer:

(A) = 3.57 m

Explanation:

from the question we are given the following:

diameter (d) = 3.2 m

mass (m) == 42 kg

angular speed (ω) = 4.27 rad/s

from the conservation of energy

mgh = 0.5 mv^{2} + 0.5Iω^{2} ...equation 1

where

Inertia (I) = 0.5mr^{2}

ω = \frac{v}{r}

equation 1 now becomes

mgh = 0.5 mv^{2} + 0.5(0.5mr^{2})(\frac{v}{r})^{2}

gh = 0.5 v^{2} + 0.5(0.5)(v)^{2}

4gh = 2v^{2} + v^{2}

h = 3v^{2} ÷ 4 g .... equation 2

  from ω = \frac{v}{r}

 v  = ωr  = 4.27 x (3.2 ÷ 2)

v = 6.8 m/s

now substituting the value of v into equation 2

h = 3v^{2} ÷ 4 g

h = 3 x (6.8)^{2} ÷ (4 x 9.8)

h = 3.57 m

8 0
2 years ago
Before you start taking measurements though, we’ll first make sure you understand the underlying concepts involved. By what meth
Svetradugi [14.3K]

Answer:

If they are metallic spheres  they are connected to earth and a charged body approaches

non- metallic (insulating) spheres in this case are charged by rubbing

Explanation:

For fillers, there are two fundamental methods, depending on the type of material.

If they are metallic spheres, they are connected to earth and a charged body approaches, this induces a charge of opposite sign and of equal magnitude, then it removes the contact to earth and the sphere is charged.

If the non- metallic (insulating) spheres in this case are charged by rubbing with some material or touching with another charged material, in this case the sphere takes half the charge and when separated each sphere has half the charge and with equal sign.

8 0
2 years ago
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