Answer:
Step-by-step explanation:
According to the central limit theorem, if independent random samples of size n are repeatedly taken from any population and n is large, the distribution of the sample means will approach a normal distribution. The size of n should be greater than or equal to 30. Given n = 100 for both scenarios, we would apply the formula,
z = (x - µ)/(σ/√n)
a) x is a random variable representing the salaries of accounting graduates. We want to determine P( x > 52000)
From the information given
µ = 50402
σ = 6000
z = (52000 - 50402)/(6000/√100) = 2.66
Looking at the normal distribution table, the probability corresponding to the z score is 0.9961
b) x is a random variable representing the salaries of finance graduates. We want to determine P(x > 52000)
From the information given
µ = 49703
σ = 10000
z = (52000 - 49703)/(10000/√100) = 2.3
Looking at the normal distribution table, the probability corresponding to the z score is 0.9893
c) The probabilities of either jobs paying that amount is high and very close.
3(15.49 + 20.82 + 22.91)
3(59.22) =
177.66 <=== what group collected
h=5 in
w-6 in
l=12 in
SA/V=2*12*6+2*6*5+2*12*5/12*6*5
817:180
This is just an example do not use this exact equation and number! Hope it helps. : )
Because he was such a good ruler
I think the answer is $113.1. The question was confusing so sorry if it’s wrong.
