<em>Answer: I think it is C</em>
Explanation: sorry if it wrong
Answer:
Speed of the cart at the top of the loop = 34.3 m/s
Explanation:
Gravitational acceleration = g = 9.81 m/s2
Your mass = m
You feel three times as heavy at the top of the loop.
Normal force on you = N = 3mg
Radius of the loop = R
Speed of the cart = V
Centripetal force required for the circular motion = Fc
F = m
The centripetal force is provided by the normal force on you which is directed downwards and your own weight which is directed downwards.
Fc = mg + N
Fc = mg + 3mg
Fc = 4mg
m12 -= 4mg R
V = 4gR
V = 4(9.81)(30)
V = 34.3 m/s
Speed of the cart at the top of the loop = 34.3 m/s
A. Evidence that supports the theory
Answer:
a) When its length is 23 cm, the elastic potential energy of the spring is
0.18 J
b) When the stretched length doubles, the potential energy increases by a factor of four to 0.72 J
Explanation:
Hi there!
a) The elastic potential energy (EPE) is calculated using the following equation:
EPE = 1/2 · k · x²
Where:
k = spring constant.
x = stretched lenght.
Let´s calculate the elastic potential energy of the spring when it is stretched 3 cm (0.03 m).
First, let´s convert the spring constant units into N/m:
4 N/cm · 100 cm/m = 400 N/m
EPE = 1/2 · 400 N/m · (0.03 m)²
EPE = 0.18 J
When its length is 23 cm, the elastic potential energy of the spring is 0.18 J
b) Now let´s calculate the elastic potential energy when the spring is stretched 0.06 m:
EPE = 1/2 · 400 N/m · (0.06 m)²
EPE = 0.72 J
When the stretched length doubles, the potential energy increases by a factor of four to 0.72 J
Two methods of transfer of heat are involved in this process: conduction and convection.
In fact, the metal spoon is heated by conduction because the molecules of the boiling water collide with the molecules of the spoon, releasing heat to it; and also by convection, because in the pot of boiling water masses of hot water goes upward and they give their heat to the spoon, then these masses become cooler and they go down, replaced by other masses of hot water.