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Gnom [1K]
2 years ago
14

A farm distributor packed 2,650 melons in boxes.each box can hold 8 melons. All the boxes are full except for one box.

Mathematics
1 answer:
laiz [17]2 years ago
7 0

Answer:

there are 331 full boxes but the one box that isnt full has two melons

Step-by-step explanation:

2,650 divided by 8 = 331

331 multiplied by 8 = 2648

2650 - 2648 = 2

so there are 332 boxes total 331 full ones and one not full on with 2 melons in it.

Hope that helps!

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Li keeps track of the time he spends working out each week. The table shows the number of cardio workouts and the number of weig
Dmitry [639]

Step-by-step explanation:

1)X represents the time he spent in cardio.

Y represents the time he spent in weighted.

2)If you could put the options on the second one it would be better.

3)4x+y=210

3x+2y=195

y=210-4x

3x+2(210-4x)=195

3x+420-8x=195

5x=420-195

5x=225

x=45

y=30

Total time of one cardi and weighted = 75min= 5/4 h.

4)2x+4y=

90+120=210 total time of week three.

4 0
2 years ago
Read 2 more answers
1. Mr. Villa bought 91.25 inches of plastic labeling tape. He will use 1.25 inches long to label each.How many labels can he mak
Cloud [144]
1.25x=91.25 now solve for x and we get x=73 so Mr. Villa can do 73 labels
5 0
2 years ago
a circle with a 12-inch diameter is folding in half and then folded in half again what is the area of the resulting shape
andrew-mc [135]

Answer:

3π in^2

Step-by-step explanation:

Area of the circle before folding = π r^2

= 6^2 π

= 36 π is^2

The area of the resulting shape  = 1/2 * 1/2 * 12π

= 3 π in^2.


7 0
2 years ago
A recent poll of 85 randomly selected cable subscribers found that 39% would be willing to pay extra for a new nature channel. T
adoni [48]
The mean is 85*0.39 = 33.15, while the standard error is sqrt(0.39*0.61/85) = 0.0529. Using the z-score of 1.96, the confidence interval is:33.15 +/- 1.96*0.0529 = (33.05, 33.25)By dividing by 85, this corresponds to a proportion of:(0.3888, 0.3912)

7 0
2 years ago
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A contaminant is leaking into a lake at a rate of R(t) = 1400e0.06t gallons/h. Enzymes have been added to the lake that neutrali
ruslelena [56]

Answer:

Step-by-step explanation:

Rate of leakage, R(t) = 1400 e^0.06t gallons/h

fraction remains , S(t) = e^(-0.32t)

initial contaminant = 1000 gallon

gallons contaminant present after t hour is S(t) R(t)

G(t) = S(t) R(t)

G(t) = 1400 e^{0.06t}\times e^{-0.32t}

G(t) = 1400 e^{- 0.26t}

Put t = 18 hours

G(t) = 1400 e^{- 0.26\times 18}

Taking log on both the sides

ln G = ln 1400 - 0.26 x 18

ln G = 7.244 - 4.68

ln G = 2.564

G = 13 gallons

5 0
2 years ago
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