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Oxana [17]
2 years ago
4

Garden delicious pea pods have lengths that are approximately normally distributed with standard deviation 0.8 inches. the large

st 1 percent of pods are eligible for prizes. how many inches above the mean pod length is the smallest pod that is eligible for a prize?
Mathematics
1 answer:
Makovka662 [10]2 years ago
6 0

Answer:

Step-by-step explanation:

Let X denotes the length of a randomly selected garden delicious pea pod.

X\sim Normal(\mu,0.8^2)


To find x such that P(X>\mu+x)=0.01


\Rightarrow P(\frac{X-\mu}{0.8}>\frac{x}{0.8})=0.01
\\\\\Rightarrow P(\frac{X-\mu}{0.8}\leq \frac{x}{0.8})=0.99
\\\\\Rightarrow \Phi(\frac{x}{0.8})=0.99
\\\\\Rightarrow \frac{x}{0.8}=\Phi^{-1}(0.99)=2.32635
\\\\\Rightarrow x=2.32635*0.8=1.86108

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Answer:7

Step-by-step explanation:

This can be solved by Venn-diagram

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also 3 among them want Spanish,french & Latin

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Also Student who want only Latin is 5

Thus Student who wants Latin and Spanish both only is 11-5-3-2=1

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2 years ago
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Answer:

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

And for this case the 95% confidence interval is given by (2.13; 2.37)

We have a point of estimate for the sample mean with this formula:

\bar X = \frac{Upper+ Lower}{2}= \frac{3.37+2.13}{2}= 2.75

And for the margin of error we have the following estimation:

ME= \frac{Upper -Lower}{2}= \frac{3.37-2.13}{2}= 0.62

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X represent the sample mean

\mu population mean (variable of interest)

s represent the sample standard deviation

n represent the sample size  

Solution to the problem

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

And for this case the 95% confidence interval is given by (2.13; 2.37)

We have a point of estimate for the sample mean with this formula:

\bar X = \frac{Upper+ Lower}{2}= \frac{3.37+2.13}{2}= 2.75

And for the margin of error we have the following estimation:

ME= \frac{Upper -Lower}{2}= \frac{3.37-2.13}{2}= 0.62

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ax+by=d where a=a, b=b, and c and d are constants

(for this answer, I'm going to use 2x+5y=15)

given 2x+5y=15, the equation of a line paralell to that is 2x+5y=d

to find d, subsitute the point (4,-2), basically put 4 in for x and -2 for y to get the constant

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pls mark me brainlest

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