Answer:
The force increases because it is part of a Newton’s third law pair of forces with the force that the star exerts on the planet.
Explanation:
Force between two objects can be expressed by an equation:
F = G • m1 • m2 / r^2,
where m1 and m2 are objects' masses, r is the distance between them, and G is a gravitational constant.
That means that greater the masses or lesser the distance, the force will be greater, and vice versa.
This force exists between any two objects, but is generally extremely weak, so it's best observed with big and large objects with great mass, such as planets and stars.
This force, whatever its magnitude may be, always works on both objects, following the third Newton's law.
So, whatever the force the stat exerts on the planet is, the planet will exert the same amount of force on the star.
Answer:
35 KJ.
Explanation:
The activation energy is the minimum energy that must be overcome for a reaction to take place.
In the diagram given above, the activation energy lies between the energy of the reactants and that at the peak.
Thus we can calculate the activation energy as follow:
Energy of reactants = 30 KJ
Energy at the peak = 65 KJ
Activation energy =..?
Activation energy = Energy at the peak – Energy of reactants
Activation energy = 65 – 30
Activation energy = 35 KJ
Therefore, the activation energy of th reaction is 35 KJ
PH of solution will be greater than seven (pH>7), that means that solution is basic (<span>pH above </span>7<span> is a base, the higher the number, the stronger is the base).
</span>pH (potential of hydrogenis) is a measure of the hydrogen ion (H⁺) concentration of a solution. <span>Solutions with a pH less than 7 are acidic.</span>
Answer:
The answer to your question is 50 moles of O₂
Explanation:
Balanced Chemical reactions
1.- N₂(g) + 3H₂ (g) ⇒ 2NH₃ (g)
2.- 4NH₃ (g) + 5O₂(g) ⇒ 4NO (g) + 6H₂O (l)
moles of N₂(g) = 20 moles
moles of O₂(g) = ?
Process
1.- Calculate the moles of NH₃
1 mol of N₂ ------------- 2 moles of NH₃
20 moles of N₂ --------- x
x = (20 x 2) / 1
x = 40 moles of NH₃
2.- Calculate the moles of O₂
4 moles of NH₃ -------------- 5 O₂
40 moles of NH₃ ------------ x
x = (40 x 5) / 4
x = 200 / 4
x = 50 moles of O₂
Hey there:
1 cm³ = 1 mL
D = m / V
7.25 = 12.9 / V
V = 12.9 / 7.25
V = 1.779 cm³
