answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
love history [14]
2 years ago
12

An astronaut is in an all-metal chamber outside the space station when a solar storm results in the deposit of a large positive

charge on the station. Which statement is correct?
a. The astronaut must abandon the chamber immediately to avoid being electrocuted.
b. The astronaut will be safe only if she is wearing a spacesuit made of non-conducting materials.
c. The astronaut does not need to worry: the charge will remain on the outside surface.
d. The astronaut must abandon the chamber if the electric field on the outside surface becomes greater than the breakdown field of air.
e. The astronaut must abandon the chamber immediately because the electric field inside the chamber is non- uniform.
Physics
1 answer:
grin007 [14]2 years ago
8 0

Answer:

c. The astronaut does not need to worry: the charge will remain on the outside surface.

Explanation:

The all-metal chamber (conductor) receives an external electromagnetic field, so it is positively charged in the direction the electromagnetic field is going, and negatively charged in the opposite direction. Since the chamber is polarized, it generates an electric field equal in magnitude, but opposite the external electromagnetic field, then the net electric field inside the conductor is 0.

You might be interested in
3-m-high large tank is initially filled with water. The tank water surface is open to the atmosphere, and a sharp-edged 10-cm-di
irinina [24]

Answer:

The initial velocity of the water from the tank is 5.42 m/s

Explanation:

By applying Bernoulli equation between  point 1 and 2

\dfrac{P_1}{\rho g}+\dfrac{V_1^2}{2g}+Z_1=\dfrac{P_2}{\rho g}+\dfrac{V_2^2}{2g}+Z_2+h_L

At the point 1

P₁=0  ( Gauge pressure)

V₁= 0 m/s

Z₁=3 m

At point 2

P₂=0  ( Gauge pressure)

Z₂= 0 m/s

h_L=1.5\ m

Now by putting the values

\dfrac{P_1}{\rho g}+\dfrac{V_1^2}{2g}+Z_1=\dfrac{P_2}{\rho g}+\dfrac{V_2^2}{2g}+Z_2+h_L

Z_1-h_L=\dfrac{V_2^2}{2g}

3-1.5=\dfrac{V_2^2}{2\times 9.81}

V_2=\sqrt{2\times 1.5\times 9.81}\ m/s

V₂= 5.42 m/s

The initial velocity of the water from the tank is 5.42 m/s

3 0
3 years ago
According to Dr. paul Narguizian professor of Biology and Science Education at California State University, ______ are generaliz
Mazyrski [523]

Answer:

I believe the correct answer would be A :)

Explanation:

3 0
1 year ago
A thin film of polystyrene is used as an antireflective coating for fabulite (known as the substrate). the index of refraction o
kvasek [131]

To solve this problem, we assume that the wavelength of the light in air is 500 nanometers.

For this case we only need the refractive index of the polystyrene. For an antireflective coating, we need a quarter of wave thickness at the wavelength in the air. Which means that the antireflective coating needs to be as thick as 1/4 of the wavelength, divided by the coating’s refractive index. This is expressed mathematically in the form:

x = λ / (4 * n)

where,

x = thickness

λ = wavelength of light

n = index of refraction of polystyrene

Substituting:

x = 500 nm / (4 * 1.49)
x = 500 nm / 5.96
x = 83.90 nm

6 0
2 years ago
Ball 1 travels with a momentum of 48.0 kg-m/s east and strikes Ball 2, which is initially at rest.. Ball 1 separates at an angle
vladimir1956 [14]

Answer:

Momentum of 2nd ball is

P = 31.6 kg m/s

direction is given as

\theta = -37.66 degree

Explanation:

As we know that there is no external force on the system of balls so momentum before and after collision will be conserved

So we have

P_i = 48 \hat i + 0

now after collision momentum of two balls is must be same as initial

so we have

P_i = P_f

48\hat i = (30 cos40 \hat i + 30 sin40\hat j) + (P_{2x}\hat i + P_{2y}\hat j)

so we have

48 = 23 + P_{2x}

P_{2x} = 25 kg m/s

for other component we have

0 = 19.3 + P_{2y}

P_{2y} = -19.3 kg m/s

Momentum of 2nd ball is given as

P = \sqrt{P_2x}^2 + P_{2y}^2}

P = 31.6 kg m/s

direction is given as

tan\theta = \frac{P_{2y}}{P_{2x}}

tan\theta = \frac{-19.3}{25}

\theta = -37.66 degree

5 0
2 years ago
A Hooke's law bowstring is stretched x meters until a force of f newtons is applied, and then held. By what factor will the elas
Liono4ka [1.6K]

The elastic potential energy increases by a factor of 9

Explanation:

The elastic potential energy of a bowstring is given by

E=\frac{1}{2}kx^2 (1)

where

k is the spring constant

x is the elongation of the bowstring

Hooke's law states the relationship between the force applied and the elongation of an elastic object:

F=kx

where

F is the force applied

x is the elongation

We can rewrite it as

x=\frac{F}{k}

And substituting into (1),

E=\frac{1}{2}k(\frac{F}{k})^2=\frac{F^2}{2k}

In  this problem, the force applied to the bowstring is tripled,

F' = 3F

So the final elastic potential energy is:

E'=\frac{(3F)^2}{2k}=9(\frac{F^2}{2k})=9E

So, the elastic potential energy increases by a factor of 9.

Learn more about potential energy:

brainly.com/question/1198647

brainly.com/question/10770261

#LearnwithBrainly

7 0
2 years ago
Other questions:
  • explain why the impact of one heavy stone would produce waves with higher amplitude than the impact of the light stone would
    6·1 answer
  • The air in tires can support a car because gases __________.
    5·1 answer
  • You and your friend Peter are putting new shingles on a roof pitched at 20degrees . You're sitting on the very top of the roof w
    5·1 answer
  • Two particles carrying charges q1 and q2 are separated by a distance r and exert an electric force F⃗ E on each other. If q1 is
    13·1 answer
  • A very tall building has a height H0 on a cool spring day when the temperature is T0. You decide to use the building as a sort o
    10·1 answer
  • A 25N force is applied to a bar that can pivot around its end. The force is r=0.75 m away from the end of an angle at 0= 30. wha
    10·1 answer
  • A solar-powered car has a kinetic energy of 110250 J. Its mass is 180 kg. Work out how fast the car is travelling.
    9·2 answers
  • A boy jumps into an indoor swimming pool. He notices that the water appears to get colder as he
    7·1 answer
  • . A little car has a maximum acceleration of 2.57 m/s2. What is the new maximum acceleration of the little car if it tows anothe
    12·1 answer
  • Listed in the Item Bank are some important labels for sections of the image below. To find out more information about labels, so
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!