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olganol [36]
2 years ago
10

A very tall building has a height H0 on a cool spring day when the temperature is T0. You decide to use the building as a sort o

f giant thermometer on a hot summer day by carefully measuring its height. Suppose you do this and discover that the building is a length h taller than it was on the cool spring day where h is much much less than H0. Assume the entire frame of the building is made of steel, which has a coefficient of linear expansion αsteel.
Required:
What is the temperature, assuming that the building is in thermal equilibrium with the air and that its entire frame is made of steel?
Physics
1 answer:
Vlada [557]2 years ago
5 0

Answer:

The temperature is   T  =  \frac{h}{H_O \alpha_{steel} }  + T_O

Explanation:

From the question we are told that

      The height on a cool spring day is H_O

      The temperature on a cool spring day is  T_O

      The difference in height between a cool spring day and a summer day  is     h

     The coefficient of static friction is \alpha _{steel}

The mathematical relation for the linear expansion of the steel buiding is represented as

               h  =  H_o \alpha_{steel}  [T-T_O]

Where T is the temperature of the steel during summer

Now making T the subject we have

                T  =  \frac{h}{H_O \alpha_{steel} }  + T_O

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A green laser pointer has a wavelength of 532 nm. what is the energy of one mol of photons generated from this device?
PSYCHO15rus [73]

We have energy E = hc/λ, where h is Planck's constant c is speed of light and λ is the wavelength.

So Energy , E=\frac{6.63*10^{-34}*3*10^8}{532*10^{-9}} =3.73*10^{-19}J

Energy of one mol = 3.73*10^{-19}*6.023*10^{23}=225 kJ/mol

Energy of one mol of photons generated from this device = 225 kJ

3 0
2 years ago
Suppose an X-ray binary is found in which the visible star is a 12 M⦿ red giant, the orbital period is 3.65 days, and the semima
nataly862011 [7]

Answer:

If the mass of a star is greater than 3 solar masses, it will create a black hole. If its mass is less, it will create a neutron star.

Explanation:

If a star's gravity is high enough, when it condenses on itself, it will form a black hole. Otherwise, it will create a large amount of highly dense matter, such as a neutron star. It can be said that if the mass of a star is greater than 3 solar masses, it will create a black hole. If its mass is less, it will create a neutron star.

8 0
2 years ago
A badger is trying to cross the street. Its velocity vvv as a function of time ttt is given in the graph below where rightwards
Mrrafil [7]

Answer: -2.5

Explanation:

1/2(-5)= -2.5

-2.5(1)= -2.5

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5 0
2 years ago
A man is dragging a trunk up the loading ramp of a mover’s truck. The ramp has a slope angle of 20.0°, and the man pulls upward
AleksandrR [38]

Answer:

(a)  104 N

(b) 52 N

Explanation:

Given Data

Angle of inclination of the ramp: 20°

F makes an angle of 30° with the ramp

The component of F parallel to the ramp is Fx = 90 N.  

The component of F perpendicular to the ramp is Fy.

(a)  

Let the +x-direction be up the incline and the +y-direction by the perpendicular to the surface of the incline.  

Resolve F into its x-component from Pythagorean theorem:  

Fx=Fcos30°

Solve for F:  

F= Fx/cos30°  

Substitute for Fx from given data:  

Fx=90 N/cos30°

   =104 N

(b) Resolve r into its y-component from Pythagorean theorem:

     Fy = Fsin 30°

   Substitute for F from part (a):

     Fy = (104 N) (sin 30°)  

          = 52 N  

5 0
2 years ago
A filamentary conductor is formed into an equilateral triangle with sides of length carrying current i . find the magnetic field
arsen [322]

magnetic field due to a finite straight conductor is given by

B = \frac{\mu_0 i}{4\pi r}(sin\theta_1 + sin\theta_2)

here since it forms an equilateral triangle so we will have

\theta_1 = \theta_2 = 60 degre

also the perpendicular distance of the point from the wire is

r = \frac{a}{2\sqrt3}

now from the above equation magnetic field due to one wire is given by

B = \frac{\mu_0 i}{4\pi \frac{a}{2\sqrt3}(sin60 + sin60)

B = \frac{\mu_0 i*2\sqrt3}{4\pi a}(\sqrt3)

B = \frac{3\mu_0 i}{2\pi a}

now since in equilateral triangle there are three such wires so net magnetic field will be

B = \frac{9\mu_0 i}{2\pi a}

5 0
2 years ago
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