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Stella [2.4K]
2 years ago
9

An experiment to measure the speed of light uses an apparatus similar to Fizeau's. The distance between the light source and the

mirror is 10 m, and the wheel has 800 notches. If the wheel rotates at 9000 rev/s when the light from the source is extinguished, what is the experimental value for c (in m/s)?
Physics
1 answer:
Marina86 [1]2 years ago
4 0

Answer:

2.88*10^{8} m/s

Explanation:

The speed of light is given by

c=\frac {2d}{t} and t=\frac {\theta}{\omega} hence

c=\omega\frac {2d}{\theta}

Speed of light is given by

c=900\times 2\pi(\frac {2\times 10}{\frac {2\pi}{2*800}}})=2.88*10^{8} m/s

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Kristina works out seven days a week. Lately, she has been tired, and her body aches. If she is overtraining, which training pri
sertanlavr [38]

Answer: Option (b) is the correct answer.

Explanation:

As Kristina is over training, therefore, there is pain in her muscles because human body also requires rest in order to work or function properly.

That is why, gym trainers suggest to give one day off in a week for your workout sessions so that body muscles should recover.

Thus, we can conclude that if Kristina is over training, then recovery training principle should Kristina consider before continuing her program.

8 0
2 years ago
The velocity component with which a projectile covers certain horizontal distance is maximum at the moment of? a) Hitting the gr
Crazy boy [7]
A) hitting the ground
3 0
2 years ago
A spaceship of frontal area 10 m2 moves through a large dust cloud with a speed of 1 x 106 m/s. The mass density of the dust is
Step2247 [10]

Answer:

The decelerating force is 3\times 10^{- 11}\ N

Solution:

As per the question:

Frontal Area, A = 10\ m^{2}

Speed of the spaceship, v = 1\times 10^{6}\ m/s

Mass density of dust, \rho_{d} = 3\times 10^{- 18}\ kg/m^{3}

Now, to calculate the average decelerating force exerted by the particle:

Mass,\ m = \rho_{d}V                                (1)

Volume, V = A\times v\times t

Thus substituting the value of volume, V in eqn (1):

m = \rho_{d}(Avt)

where

A = Area

v = velocity

t = time

m = \rho_{d}(A\times v\times t)                  (2)

Momentum,\ p = \rho_{d}(Avt)v = \rho_{d}Av^{2}t

From Newton's second law of motion:

F = \frac{dp}{dt}

Thus differentiating w.r.t time 't':

F_{avg} = \frac{d}{dt}(\rho_{d}Av^{2}t) = \rho_{d}Av^{2}

where

F_{avg} = average decelerating force of the particle

Now, substituting suitable values in the above eqn:

F_{avg} = 3\times 10^{- 18}\times 10\times 1\times 10^{6} = 3\times 10^{- 11}\ N

4 0
2 years ago
Dane is holding an 8 kilogram box 2 metres above the ground. How much energy is in the box's gravitational potential energy stor
9966 [12]

156.8 Joules of energy is in the box's gravitational potential energy store

<u>Explanation</u>:

<em>Given:</em>

Mass of the box Dane is holding = 8 Kilograms

Height at which Dane is holding the box above the ground= 2 metres

<em>To Find:</em>

Gravitational potential energy in the box=?

<em>Solution:</em>

gravitational potential energy is the work done per mass on a object to move that object from one fixed location to to another location against gravity.Its unit is joules or J

Thus  Gravitational potential energy is  represented as,

PE_g=mgh

where

PE_g is the gravitational potential energy

m is the mass

h is the height

g is the gravitational force( 9.8 m/s^2)

Now substituting the given values,

PE_g=8\times 9.8\times 2

PE_g=156.8 Joules

4 0
2 years ago
During a family trip to Laura's grandmother's house, the family cast traveled a distance of of 8 miles in 24 minutes. During the
Vanyuwa [196]

The correct answer is B

4 0
2 years ago
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