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DaniilM [7]
1 year ago
9

When the computer is started, a bootstrap or IPL (Initial Program Load) begins testing the system. Where is this bootstrap progr

am stored? A) RAM B) ROM C) Hard drive D) Virtual memory
Computers and Technology
1 answer:
aniked [119]1 year ago
7 0

Answer:

The correct answer to the following question will be Option B (ROM).

Explanation:

Bootstrap is the programming which initializes the OS during initialization. The bootstrap loader creates small operator programs that connect and monitor the various computer hardware components.

ROM is Read-only memory, which will be used to hold a computer's start-up commands, also recognized as firmware.

No other method was used to help save system startup. ROM, then, is the right answer.

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When long labels are required, which of these commands can you use to improve readability of a worksheet?
Morgarella [4.7K]
I believe it is wrap text! Hope this helped
6 0
2 years ago
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Mile markers appear as _____ green signs.
german

Answer:

A.Big,Rectangular

Explanation:

mile markers are sign on high ways they are green signs they are big and rectangular shape

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1 year ago
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Given a int variable named yesCount and another int variable named noCount and an int variable named response write the necessar
sergejj [24]

// This command takes input from the user.

Scanner input = new Scanner(System.in);

int response= input.nextInt();

// Making the variables required

int noCount =0 ;

int yesCount =0;

// Checking the response if it is 1 or 2 and reporting accordingly

if(response == 1 || response ==2){

 yesCount+=1;

 System.out.println("YES WAS RECORDED");

}

// Checking if the input is 3 or 4 then printing the required lines

else if (response == 3 || response ==4){

noCount+=1;

 System.out.println("NO WAS RECORDED");

}

// if the input is not valid than printing INVALID

else{

System.out.println("INVALID");

}

 

 

 

6 0
2 years ago
1. What might you say to someone whose reason for investing in 90% bonds and 10% stocks is that they want a 6% return on investm
Gemiola [76]

Investing in 90% bonds and 10% stocks will provide an average return of 6% on investment.It is advisable to invest more portion in bonds  is safe and will give higher return for investment than stocks

Explanation:

1. According to the graph investing in 90% bonds and 10% stocks will provide an average return of 6% on investment.

2.Investing in bonds is safe than stocks ., because bonds bear fixed rate of interest ., and investing in the bonds having very less risk than the stocks. By comparing stocks and bonds with the help of graph ., it's very clear bonds has a positive growth starting minimum at 32.6% to maximum at 64.2% as returns .But stocks has a negative growth (value) from -8.2% to maximum -43.1% .,It is advisable to invest more portions in bonds is safe and better than invest in stocks.

5 0
2 years ago
We have said that the average number of comparisons need to find a target value in an n-element list using sequential search is
bija089 [108]

Answer:

Part a: If the list contains n elements (where n is odd) the middle term is at index (n-1)/2 and the number of comparisons are (n+1)/2.

Part b: If the list contains n elements (where n is even) the middle terms are  at index (n-2)/2 & n/2 and the number of comparisons are (n+2)/2.

Part c: The average number of comparisons for a list bearing n elements is 2n+3/4 comparisons.

Explanation:

Suppose the list is such that the starting index is 0.

Part a

If list has 15 elements, the middle item would be given at 7th index i.e.

there are 7 indices(0,1,2,3,4,5,6) below it and 7 indices(8,9,10,11,12,13,14) above it. It will have to run 8 comparisons  to find the middle term.

If list has 17 elements, the middle item would be given at 8th index i.e.

there are 8 indices(0,1,2,3,4,5,6,7) below it and 8 indices(9,10,11,12,13,14,15,16) above it.It will have to run 9 comparisons  to find the middle term.

If list has 21 elements, the middle item would be given at 10th index i.e.

there are 10 indices (0,1,2,3,4,5,6,7,8,9) below it and 10 indices (11,12,13,14,15,16,17,18,19,20) above it.It will have to run 11 comparisons  to find the middle term.

Now this indicates that if the list contains n elements (where n is odd) the middle term is at index (n-1)/2 and the number of comparisons are (n+1)/2.

Part b

If list has 16 elements, there are two middle terms as  one at would be at 7th index and the one at 8th index .There are 7 indices(0,1,2,3,4,5,6) below it and 7 indices(9,10,11,12,13,14,15) above it. It will have to run 9 comparisons  to find the middle terms.

If list has 18 elements, there are two middle terms as  one at would be at 8th index and the one at 9th index .There are 8 indices(0,1,2,3,4,5,6,7) below it and 8 indices(10,11,12,13,14,15,16,17) above it. It will have to run 10 comparisons  to find the middle terms.

If list has 20 elements, there are two middle terms as  one at would be at 9th index and the one at 10th index .There are 9 indices(0,1,2,3,4,5,6,7,8) below it and 9 indices(11,12,13,14,15,16,17,18,19) above it. It will have to run 11 comparisons  to find the middle terms.

Now this indicates that if the list contains n elements (where n is even) the middle terms are  at index (n-2)/2 & n/2 and the number of comparisons are (n+2)/2.

Part c

So the average number of comparisons is given as

((n+1)/2+(n+2)/2)/2=(2n+3)/4

So the average number of comparisons for a list bearing n elements is 2n+3/4 comparisons.

6 0
2 years ago
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