Old aspirin exposed to moisture often smells like acetic acid (vinegar). When aspirin is heated in boiling water, it decomposes
and gives off a vinegar smell. The resulting solution gives a positive FeCl3 test. Why is this test positive? (Please explain in detail!)
Write the chemical equation for the reaction of aspirin and water at high temperature.
Write the chemical equation for the reaction of aspirin and water at high temperature.
1 answer:
Explanation:
Vinegar like smell is given off by aspirin when we tend to heat it in boiling water. The main cause of this vinegar like smell is due to the formation of acetic acid and a phenolic acid upon heating of aspirin.
As a result, it gives a positive test when treated with ferric chloride, that is, .
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Answer:
The equilibrium concentration of CH₃OH is 0.28 M
Explanation:
For the reaction: CO (g) + 2H₂(g) ↔ CH₃OH(g)
The equilibrium constant (Keq) is given for the following expresion:
Keq= =14.5
Where (CH3OH), (CO) and (H2) are the molar concentrations of each product or reactant.
We have:
(CH3OH)= ?
(CO)= 0.15 M
(H2)= 0.36 M
So, we only have to replace the concentrations in the equilibrium constant expression to obtain the missing concentration we need:
14.5=
14.5 x (0.15 M) x = (CH₃OH)
0.2818 M = (CH₃OH)
Answer : The value of ΔH for this reaction is, -1516 kJ/mol
Explanation :
First we have to calculate the moles of
Now we have to calculate the ΔH for this reaction.
As, 2.5 mole of react to gives heat = -3790 kJ
So, 1 mole of react to gives heat =
= -1516 kJ/mol
Therefore, the value of ΔH for this reaction is, -1516 kJ/mol