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sergiy2304 [10]
2 years ago
15

The displacement z of a particle of rest mass m0, resulting from a constant force m0g along the z-axis is including relativistic

effect. Find the displacement z as a power series in time t. Compare with the classical result,

Physics
1 answer:
Debora [2.8K]2 years ago
3 0

Hi, your question was incomplete, hence I am writing down the complete question below.

Q)The displacement x of a particle of rest mass m0, resulting from a constant force m0g along the  x-axis, is

x= c2/g{[1+(gt/c)2]power0.5-1}

including relativistic effects. Find the displacement x as a power series in time t. Compare with  the classical result.

Answer:

<h3>Please refer to the attachment below.</h3>

Explanation:

<h3>Please refer to the attachment below for explanation.</h3>

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Answer:

Fa=774 N

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Explanation:

We will solve this problem by equating forces on each axis.

  1. On x-axis let forces in positive x-direction be positive and forces in negative x-direction be negative
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While towing we know that car is mot moving in y-direction so net force in y-axis must be zero

⇒∑Fy=0

⇒Fa*sin(50)-Fb*sin(20)=0

⇒Fa*sin(50)=Fb*sin(20)

⇒Fa=2.24Fb

Given that resultant force on car is 950N in positive x-direction

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⇒2.24*Fb*cos(20)+Fb(50)=950

⇒Fb*(2.24*cos(20)+cos(50))=950

⇒Fb=\frac{950}{2.24*cos(20)+cos(50)}

⇒Fb=\frac{950}{2.24*0.94+0.64}

⇒ Fb=\frac{950}{2.75}=345.5

⇒Fa=2.24*Fb

      =2.24*345.5

      =773.93

Therefore approximately, Fa=774 N and Fb=346 N

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let the length of the beam be "L"

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m = mass of beam = 20 kg

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