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FrozenT [24]
2 years ago
6

What is the potential difference between the terminals of an ordinary AA or AAA battery? (If you’re not sure, find one and look

at the label.)
Physics
1 answer:
julia-pushkina [17]2 years ago
7 0
AA means it has a thinner mass than A, and AAA means it has a thinner mass than AA. So, their thickness is varied according to the equipment in which these are to be used. Therefore, the potential difference between the terminals of an ordinary AA battery or ordinary AAA battery is .
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What is Otter's average velocity over his entire trip when it takes him 2 minutes to walk 100 meters north and another 1 minute
Leya [2.2K]

Answer:

0.50m/s

Explanation:

Average velocity is the change in displacement of a body with respect to time.

Velocity = ∆S/∆t

∆S = 100m - 70m

∆S = 30m

∆t = 2min - 1 min

∆t = 1min = 60secs

Substitute the given parameters into the formula for velocity

Velocity = 30m/60s

Velocity = 1/2 m/s

Average Velocity = 0.5m/s

7 0
2 years ago
A truck pulled a car of 2,350 kg a distance of 25 meters. If the car accelerates from 3 m/s to 6 m/s, whats the average force ex
faust18 [17]

Answer:

1,269 N

Explanation:

4 0
2 years ago
A huge (essentially infinite) horizontal nonconducting sheet 10.0 cm thick has charge uniformly spread over both faces. The uppe
Nonamiya [84]

Answer:

6.78 X 10³ N/C

Explanation:

Electric field near a charged infinite plate

=  surface charge density / 2ε₀

Field will be perpendicular to the surface of the plate for both the charge density and direction of field will be same so they will add up.

Field due to charge density of +95.0 nC/m2

E₁ = 95 x 10⁻⁹ / 2 ε₀

Field due to charge density of -25.0 nC/m2

E₂ = 25 x 10⁻⁹ /  2ε₀

Total field

E = E₁ + E₂

= 95 x 10⁻⁹ / 2 ε₀ + 25 x 10⁻⁹ /  2ε₀

= 6.78 X 10³ N/C

4 0
2 years ago
Trained dolphins are capable of a vertical leap of 7.0 m straight up from the surface of the water - an impressive feat. Suppose
dmitriy555 [2]

Answer:14 m

Explanation:

Given

Vertical jump make by the dolphin is given by h=7\ m

Suppose the dolphin jump with an initial velocity of u

so u is given by u^2=2\cdot g\cdot h

If dolphin launches at an angle \theta then maximum horizontal range is given by

assuming the of Dolphin to be Projectile so range is given by

R=\frac{u^2\sin 2\theta }{g}

substitute the value of u^2

R=\frac{2\times 9.8\times 7\sin 2\theta }{9.8}

R=2h\sin 2\theta

Range will be maximum for \theta =45^{\circ}

thus R_{max}=2\times 7\times 1=14\ m

                                     

3 0
2 years ago
Two speakers, A and B, produce identical sound waves. A listener is 3.2 m away from speaker A. The listener finds the lowest fre
earnstyle [38]

Answer:

  0.83 m or 5.57 m

Explanation:

Destructive interference will occur when the distances from the speakers differ by 1/2 wavelength.

The length of 1 cycle of 72.4 Hz is ...

  λ = v/f = (343 m/s)/(72.4 Hz) ≈ 4.738 m

So, the distance of the listener from speaker B is ...

  3.2 m ± (4.738 m)/2 = {0.83 m, 5.57 m} . . . either of these distances

_____

The location could be at additional multiples of 4.738 m, but we think not. The sound intensity drops off with the square of the distance from the speaker, so identical sound waves from the speakers will sound quite different at different distances from the speakers. For best interference, the distances need to be as close to the same as possible. That will be at 3.2 m and 5.57 m.

_____

<em>Comment on the speed of sound</em>

We don't know what speed you are to use for the speed of sound. We have used 343 m/s. Some sources use 340 m/s, which will give a result different by 2 or 3 cm.

8 0
2 years ago
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