A mine car, whose mass is 440kg, rolls at a speed of 0.50m/s on ahorizontal track, as the drawing shows. A 150kg chunk of coalha
1 answer:
Answer: 0.56 m/s
Explanation:
hello, there is 25° inclination angle for the chute in the drawing. Thankfully, I know this problem. The conservation of momentum.
so there are X and Y components for the momentum in this problem. The Y component is not conserved as when the coal gets in the cart, the normal force exerted by the surface reduces it to 0.
Now, the X component is definitely conserved here.
so you have the momentum of the cart which is 440*0.5 added to the momentum of the chunk which is 150*0.8*cos(25°), that is the momentum before the coupling between the objects. Afterwards both objects will have the same velocity, so we write the equation like this:
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The density of a material is constant and it is given by the ratio of the mass to the volume of the material
The mass of the liquid and the full bottle ae
The mass of the liquid is <u>450 g</u>
The mass of the filled bottle is <u>530 grams</u>
<u></u>
The reason the above values are correct are as follows:
The given parameters are;
Volume of the bottle, V = Half litre
Mass of the bottle, = 80 g
The volume of liquid in the bottle when filled, V = 500 cm³
The density of the olive oil with which the bottle is filled, ρ = 0.9 g/cm³
a. Required:
To calculate the mass of oil in the bottle
Solution:
The volume of oil in the bottle when the bottle is filled, V = 500 cm³
The mass of the liquid, m = ρ × V
∴ m = 0.9 g/cm³ × 500 cm³ = 450 g
The mass of the liquid, m = <u>450 g</u>
<u></u>
b. The mass of the oil in the bottle, m = grams
The mass of the full bottle, = m +
∴ = 450 g + 80 g = 530 g
The mass of the full bottle, = <u>530 grams</u>
Learn more about density here:
Answer:
V=20cm/s
Explanation:
The average speed is the distance total divided the time total:
First stage:
T1=5s
But, (decelerates to rest)
then:
on the other hand:
X1=75cm
Second stage:
T2=5s
X2=125cm
Finally:
X=X1+X2=200cm
T=T1+T2=10s
V=X/T=20cm/s
Answer:
<em>a) 17.05 mph</em>
<em>b) 54.7° northeast direction</em>
<em>c) 10.71 mph</em>
<em>The direction is -22.58° relative to the east.</em>
<em></em>
<em>To head northeast, you must either increase your gliding speed or increase your angle relative to the x-axis greater than 45°.</em>
Explanation:
The question is a little confusing but, I guess the correct question should be;
You are flying a hang glider at 14 mph in the northeast direction (45°). The wind is blowing at 4 mph due north.
a) What is your airspeed?
b) What angle (direction) are you flying?
c) The wind increases to 14 mph from north. Now what is your airspeed and what direction are you flying? If your destination is to the northeast, how would you change your speed or direction so you might make it there?
NB: The difference in the question and my suggestion is highlighted boldly.
Your speed = 14 mph
direction is 45° northeast
Th wind speed = 4 mph
direction is north
We resolve the your speed and the wind speed into the horizontal and vertical components
For vertical the component component
= 14(sin 45) + 4 = 9.89 + 4 = 13.89 mph
For the horizontal speed component
= 14(cos 45) + 0 = 9.89 + 0 = 9.89 mph
Resultant speed =
==> = <em>17.05 mph This is your airspeed</em>
b) To get your direction, we use
tan ∅ = /
tan ∅ = 13.89/9.89 = 1.413
∅ = (1.413) = <em>54.7° northeast direction</em>
c) If the wind increases to 14 mph from the north, then it means the wind blows due south. As before, only the vertical component is affected .
In this case,
= 14(sin 45) - 14 = 9.89 - 14 = -4.11 mph
Resultant speed =
==> = <em>10.71 mph This is your airspeed</em>
Your direction will be,
tan ∅ = /
tan ∅ = -4.11/9.89 = -0.416
∅ = (-0.416) =<em> -22.58° this is the angle you'll travel relative to the east.</em>
<em>To head northeast, you must either increase your gliding speed or increase your angle relative to the x-axis greater than 45°.</em>
Answer:
Explanation:
The speed of light is given by
and
hence
Speed of light is given by