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Mrrafil [7]
2 years ago
14

The magnitude of the resultant force is to be 200 N, directed along the positive ݒaxis. Determine the magnitude of the force Fin

d the angle θ.

Physics
1 answer:
Ilia_Sergeevich [38]2 years ago
3 0

Answer: F = 776.18N θ = 29.41°

Question:

The magnitude of the resultant force is to be 200 N, directed along the positive y-axis. Determine the magnitude of the force F Find the angle θ.

Attached is the image.

Explanation:

To solve this question we need to resolve the forces to the x and y axis.

For the x axis;

Fcosθ = 700cos15....1

For the y axis;

200 = Fsinθ - 700sin15

Fsinθ = 200 + 700sin15 ...2

Dividing equation 2 by 1

Fsinθ/Fcosθ = (200 + 700sin15)/700cos15

Tanθ = (200 + 700sin15)/700cos15

θ = Taninverse(200 + 700sin15)/700cos15)

θ = 29.41°

From equation 1;

F = 700cos15/cosθ

F = 700cos15/cos29.41

F = 776.18N

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In certain cases, using both the momentum principle and energy principle to analyze a system is useful, as they each can reveal
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Explanation:

We are given;

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Plugging in the relevant values, we have;

F_g = (6.67 × 10^(-11) × 3500 × 6 x 10²⁴)/(7.3 x 10⁶)²

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B) From the momentum principle, we have that the gravitational force is equal to the centripetal force.

Thus;

GmM/r² = mv²/r

Making v th subject, we have;

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Plugging in the relevant values;

v = √(6.67 × 10^(-11) × 6 x 10²⁴)/(7.3 x 10⁶))

v = 7404.18 m/s

C) From the energy principle, the minimum amount of work is given by;

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Plugging in the relevant values;

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5 0
2 years ago
According to a rule-of-thumb. every five seconds between a lightning flash and the following thunder gives the distance to the f
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notice how the ratios were written in such a way that the units got cancelled when calculating them. Notice that in one ratio the miles were on the numerator of the fraction while on the other they were on the denominator, which allows us to cancel them. The same happened with the feet.

The problem asks us to express the answer to one significant figure so the speed of sound rounds to 300m/s.

For the second part of the problem we need to use conversions again. This time we will write our ratios backwards and take into account that there are 1000m to 1 km, so we get:

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This means that for every 3.11s there will be a distance of 1km from the place where the lightning stroke. Since this is a rule of thumb, we round to the nearest integer for the calculations to be made easily, so the rule goes like this:

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p = 12 *10^6 kg*m/s
Final momentum:
p = 10000 * 900
p = 9 000 000
p = 9 *10^6 kg*m/s

7 0
2 years ago
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