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professor190 [17]
2 years ago
4

In the United States, the generation of people born between 1946 and 1964 are known as baby boomers, and the generation of peopl

e born between 1981 and 1996 are known as millennials. Currently, 18 percent of the population are baby boomers and 27 percent of the population are millennials. A random sample of 500 people will be selected. Let the random variable B represent the number of baby boomers in the sample, and let the random variable M represent the number of millennials in the sample. By how much will the mean of M exceed the mean of B
Mathematics
1 answer:
Irina-Kira [14]2 years ago
4 0

Answer:

45

Step-by-step explanation:

B = .18

M = .27

Sample size = 500

B(500) = 500(.18) = 90

M(500) = 500(.27) = 135

135 - 90 = 45

The mean of M will exceed the mean of B by 45 people when the sample size is 500.

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Suppose that 3% of the 2 million high school students who take the SAT each year receive special accommodations because of docum
icang [17]

Answer:

See attachment for detailed answer.

Step-by-step explanation:

Download pdf
8 0
2 years ago
The price of a math book after a discount of 25% is $36. What is the original price of the math book?
UNO [17]
If $36=75%,
That means we can divide both sides by three to get $12=25%,
And because 25x4 is 100, we multiply both sides of the equation by 4 to get $48=100%,
So the answer is $48 dollars.

This also worked for me but I’m not sure it’s the most reliable way:
36 ÷ 0.75 = 48
(amount after discount ÷ percentage that is remaining)
3 0
2 years ago
T= 300 (d−15) 2 ​ +20space, T, equals, start fraction, left parenthesis, d, minus, 15, right parenthesis, start superscript, 2,
stealth61 [152]

As can be read from your statement written "T, equals, start fraction, left parenthesis, d, minus, 15, right parenthesis, strt superscript, 2, end superscript, divided by, 300, end fraction, plus, 20", I hope your model equation is this :

T = \frac{(d-15)^{2}}{300}  + 20

Hope this is your question, if not I think you will, still be able to find an answer of your question based on this solution

As we have to find lowest average temperature, So for minimum of a function its derivative is equal to 0 there.

So lets find derivative of T function first

So first expand (d-15)^{2} as (d-15)(d-15)

we will use FOIL to multiply these

so (d-15)(d-15) = d^{2} -15d -15d +225

= d^{2} -30d +225

so we have T = \frac{d^{2} -30d +225}{300} +20

Now we will derivate each term here,300 in denominator is constant so that will come as it in in denominator.

To derivate terms in dx^{2} -30d +225 we will use power rule formula:

(x^{n} )'= nx^{n-1}

so derivative of (d^{2} )'= 2d^{2-1} = 2d^{1} = 2d

Then derivative of d will be 1

so that of -30d will be -30

then derivate of constant -225 will be 0

so we will have derivative as \frac{2d-30}{300} for the fraction part and then derivative of +20 is again 0 as its constant term

T' = \frac{2d-30}{300}

For minimum we will put this derivative =0

0 = \frac{2d-30}{300}

Now solve for d

times both sides by 300

0 \times 300 = \frac{2d-30}{300} \times 300

0 = 2d-30

0 +30 = 2d -30 +30

30 = 2d

\frac{30}{2} = \frac{2d}{2}

15 = d

So now we have to find value of lowest temperature.

For that simply plug 15 in d place in original T function equation

T = \frac{(d-15)^{2}}{300}  + 20

T = \frac{(15-15)^{2}}{300}  + 20

T = 20

So T = 20 °C is the lowest average temperature and the answer.

6 0
2 years ago
Read 2 more answers
Can somone give me the answer to 2 x 0
marshall27 [118]
Any number times 0 is going to equal 0
8 0
2 years ago
Read 2 more answers
Malcolm and Ravi raced each other.
Semenov [28]

Malcolm maximum speed is 200 km/h and Ravi maximum speed is 320 km/h

Step-by-step explanation:

Lets assume Malcolm maximum speed to be M km/h and Ravi  maximum speed to be R km/h

Average of their maximum speed is; (M+R)/2 =260 km/h

This can be simplified to M+R= 260*2

M+R = 520.......................................(I)

When Malcolm's speed is doubled,

2M=R+80 km/h ----------------------(ii)

The two equations are;

M+R = 520 ------ M=520-R ----(i)

2M=R+80 ---------------------------(ii)

Replacing M with (i) above

2M=R+80

2(520-R) =R+80

1040 -2R =R+80

1040-80 = R+2R

960 = 3R

960/3 =R

320 =R

M+R =520

M=520-320 =200

Malcolm maximum speed is 200 km/h and Ravi maximum speed is 320 km/h

Learn More

Simultaneous equations:brainly.com/question/12919422

Keywords: Average, maximum, speeds, doubled,

#LearnwithBrainly

3 0
2 years ago
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