Answer:
Part A - 3N/m
Part B - see attachment
Part C - 4.9 × 10-³J
Part D - E = 1/2kd² + 1/2mv² + mgh
Explanation:
This problem requires the knowledge of simple harmonic motion for cimplete solution. To find the spring constant in part A the expression relating the force applied to a spring and the resulting stretching of the spring (hooke's law) is required which is F = kx.
The free body diagram can be found in the attachment. Fp(force of pull), Ft(Force of tension) and W(weight).
The energy stored in the pring as a result of the stretching of d = 5.7cm is 1/2kd².
Part D
Three forces act on the spring-monkey system and they do work in different forms: kinetic energy 1/2mv² , elastic potential
energy due to the restoring force in the spring or the tension force 1/2kd², and the gravitational potential energy mgh of the position of the system. So the total energy of the system E = 1/2kd² + 1/2mv² + mgh.
