Answer:
acceleration = 2.4525 m/s²
Explanation:
Data: Let m1 = 3.0 Kg, m2 = 5.0 Kg, g = 9.81 m/s²
Tension in the rope = T
Sol: m2 > m1
i) for downward motion of m2:
m2 a = m2 g - T
5 a = 5 × 9.81 m/s² - T
⇒ T = 49.05 m/s² - 5 a Eqn (a)
ii) for upward motion of m1
m a = T - m1 g
3 a = T - 3 × 9.8 m/s²
⇒ T = 3 a + 29.43 m/s² Eqn (b)
Equating Eqn (a) and(b)
49.05 m/s² - 5 a = T = 3 a + 29.43 m/s²
49.05 m/s² - 29.43 m/s² = 3 a + 5 a
19.62 m/s² = 8 a
⇒ a = 2.4525 m/s²
If speed = distance/time , then time = speed/distance.
So...
Speed of light = 3*10^8(m/s)
Average distance from Earth to Sun = 149.6*10^9(m)
Therefore, t=(3*10^8(m/s))/(149.6*10^9(m))
I hope this was a helpful explanation, please reply if you have further questions about the problem.
Good luck!
The technique used is most likely Bandwagon.
So, B.
I believe it's B. the transmission of heat across matter
Answer:
v = 36.667 m/s
Explanation:
Knowing the rotational inertia as
Lₙ = 550 kg * m²
r = 1.0 m
m = 30.0 kg
To determine the minimum speed v must have when she grabs the bottom
Lₙ = I * ω
I = ¹/₂ * m * r²
I = ¹/₂ * 30.0 kg * 1.0² m
I = 15 kg * m²
Lₙ = I * ω ⇒ ω = Lₙ / I
ω = [ 550 kg * m² /s ] / ( 15 kg * m² )
ω = 36.667 rad /s
v = ω * r
v = 36.667 m/s