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Leviafan [203]
2 years ago
9

A 2.0m long pendulum is released from rest when the support string is at an angle of 25 degrees with the vertical. What is the s

peed of the bob at the bottom of the swing?
Physics
1 answer:
Blizzard [7]2 years ago
8 0

Answer:

v=1.92m/s

Explanation:

Given data

Length h=2.0m

Angle α=25°

To find

Speed of bob

Solution

From conservation of energy we know that:

P.E=K.E\\mgh=(1/2)mv^{2}\\ gh=(1/2)v^{2}\\v^{2}=\frac{gh}{0.5}\\ v=\sqrt{\frac{gh}{0.5}}\\ v=\sqrt{\frac{(9.8m/s^{2} )(2.0-2.0Cos(25^{o} ))}{0.5}}\\v=1.92m/s

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