An oil drop of mass 3.25X10^-15 kg falls vertically with uniform velocity, through the air between vertical parallel plates whic
h are 2 cm apart. When a p.d. of 1000V is applied to the plates ,the drop moves to the positively charged plate, being inclined at 45 degree to the vertical . Calculate the charge on the drop.
1 answer:
You might be interested in
The density of a material is constant and it is given by the ratio of the mass to the volume of the material
The mass of the liquid and the full bottle ae
The mass of the liquid is <u>450 g</u>
The mass of the filled bottle is <u>530 grams</u>
<u></u>
The reason the above values are correct are as follows:
The given parameters are;
Volume of the bottle, V = Half litre
Mass of the bottle, = 80 g
The volume of liquid in the bottle when filled, V = 500 cm³
The density of the olive oil with which the bottle is filled, ρ = 0.9 g/cm³
a. Required:
To calculate the mass of oil in the bottle
Solution:
The volume of oil in the bottle when the bottle is filled, V = 500 cm³
The mass of the liquid, m = ρ × V
∴ m = 0.9 g/cm³ × 500 cm³ = 450 g
The mass of the liquid, m = <u>450 g</u>
<u></u>
b. The mass of the oil in the bottle, m = grams
The mass of the full bottle, = m +
∴ = 450 g + 80 g = 530 g
The mass of the full bottle, = <u>530 grams</u>
Learn more about density here:
Answer:
The workdone is
Explanation:
The free body diagram is shown on the first uploaded image
From the question we are given that
The force is on the force gauge
The distance that Magnus pulled the bus
Generally the workdone by the tension force on Magnus is
This negative sign show that is tension force is in the opposite direction to Magnus movement (i.e the movement of the bus )
Substituting value we have
