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Savatey [412]
2 years ago
4

A ball attached to a string is being swung in a clockwise circular path as shown in figure 3-1. Assume the string breaks at poin

t A. In which direction will the ball be traveling an instant later?

Physics
1 answer:
Iteru [2.4K]2 years ago
3 0

Answer:

the direction is the option d

Explanation:

At the moment when the ball is turned, it acquires a tangential speed that depends on the speed of rotation and the radius of rotation. This tangential velocity to the curvature causes the point A to be fired tangentially in the direction of spin, the centripetal force disappears as the string is cut so only the tangential component will exist.

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Changes that occur in the urinary system with aging include all of the following, EXCEPT
Sladkaya [172]

Answer: c. increased sensitivity to ADH

Explanation:

a. a decline in the number of functional nephrons: With aging the loss of nephron occurs that can be detected by the age related decrease in the glomerular filteration rate.

b. a reduction in the GFR (glomerular filtration rate): The GFR tend to decline in older age even though there is no disease. These people are required to check with the GFR in future.

d. problems with the micturition reflex: With aging people experience problem of bladder control. This leads to leakage or incontinence of urine or urinary retention that is inability to empty the bladder.

e. loss of sphincter muscle tone: With age the sphincter tone may diminish. This results in loss of control and storage capacity. The rectal muscles or sphincter muscles get loose which lead to passage of stool before reaching the washroom.

6 0
2 years ago
Centripetal force Fc acts on a car going around a curve. If the speed of the car were twice as great, the magnitude of the centr
kondaur [170]

Answer:

We need 4 times more force to keep the car in circular motion if the velocity gets double.

Explanation:

Lets take the mass of the car = m

The radius of the arc = r

F=\frac{m\times v^2}{r}

Given that speed of the car gets double ,v' = 2 v

Then the force on the car = F'

F'=\frac{m\times v'^2}{r}  ( radius of the arc is constant)

F'=\frac{m\times (2v)^2}{r}

F'=4\times \frac{m\times v^2}{r}

We know that F=\frac{m\times v^2}{r}

Therefore F' = 4 F

So we can say that we need 4 times more force to keep the car in circular motion if the velocity gets double.

6 0
2 years ago
Consider two capacitors with unequal capacitance connected in parallel to a battery. Which of the following statements are true?
Allisa [31]

Answer:

  1. The equivalent capacitance of the combination is greater than the capacitance of either of the capacitors.
  2. The voltage across each of the capacitors is the same.
  3. The sum of the charge stored on each capacitor is equal to the charge supplied by the battery.

Explanation:

The capacitance connected in parallel will have the same potentials across its ends. If the battery has a charge Q, it is divided among the capacitors.

That is,

                      Q = q₁ + q₂ + q₃

But, the potential is shared equally as V. So, the individual capacitance of the equation has the form q₁ = C₁V , q₂ = C₂V, etc.

                   

So, in this case, when the effective capacitance is formulated, it would be

                          C = C₁ + C₂ + C₃     farad

Therefore, the true statements are

The equivalent capacitance of the combination is greater than the capacitance of either of the capacitors.

The potential across each of the capacitors is the same.

The charge supplied by the battery divided among the capacitors.

3 0
2 years ago
What are disadvantages and advantages of parallel circuits
kozerog [31]
Well,

Parallel circuits are circuits that have only one "line" running through all the appliances in the circuit.

A parallel circuit can be more advantageous to a series circuit because you do not have to use as much wire.

However, the fact that the current must run through every appliance could be a problem.  The most common is when an appliance (say a light bulb) wears out or breaks.

There is no longer a complete connection, and we now have an open circuit.

The parallel circuit I find the most annoying is Christmas Tree lights, where when one light bulb goes bad, all the other bulbs in that line go out.
4 0
2 years ago
Two astronauts, each having a mass of 75.0 kg, are connected by a 10.0-m rope of negligible mass. They are isolated in space, or
butalik [34]

Answer:

a) 3750 kgm²/s

b) 1875 J

c) 3750 kgm²/s

d) 10 m/s

e) 7500 J

f) 5625 J

Explanation:

a)

d = distance between the two astronauts = 10 m

m = mass of each astronaut = 75 kg

v = speed of each astronaut = = 5 m/s

r = distance of each astronaut from center of mass = (0.5) d = (0.5) (10) = 5 m

L_{s} = Angular momentum of the system

Angular momentum of the system is given as

L_{si} = 2 m v r

L_{si} = 2 (75) (5) (5)

L_{si} = 3750 kgm²/s

b)

Rotational energy of the system is given as

R_{si} = 2 (0.5) m v²

R_{si} = 2 (0.5) (75) (5)² = 1875 J

c)

L_{sf} = Angular momentum of the system after pulling

Using conservation of angular momentum,

L_{sf} = L_{si}

L_{sf} = 3750 kgm²/s

d)

r' = new distance of each astronaut from center of mass = (0.5) r = (0.5) (5) = 2.5 m

v' = new speed of each astronaut

Angular momentum of the system after pulling is given as

L_{sf} = 2 m v' r'

3750 = 2 (75) (2.5) v'

v' = 10 m/s

e)

Rotational energy of the system after pulling the rope is given as

R_{sf} = 2 (0.5) m v'²

R_{sf} = 2 (0.5) (75) (10)² = 7500 J

f)

W = work done by astronaut in pulling the rope

Work done is given as

W = R_{sf} - R_{si}

W = 7500 - 1875

W = 5625 J

3 0
2 years ago
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