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Stolb23 [73]
2 years ago
10

A crane lifts a 425 kg steel beam vertically a distance of 66 m. How much work does the crane do on the beam if the beam acceler

ates upward at 1.8 m/s2? Neglect frictional forces ...?
Mathematics
2 answers:
Fiesta28 [93]2 years ago
6 0
<span>The solution to the problem is as follows:

W=Fd=mad=425*1.8*66 =50490 J

Therefore, it takes </span><span>50490 J of work the crane will do to accelerate the beam upward at 1.8 m/s^2.

I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!

</span>
Guest1 year ago
0 0

425 x 66 x 9.81 = 275170.5 J = 2.75 X 10 ^5 J = 275.17 kJ

Guest
1 year ago
then, minus 425 x 1.8 x 66 = 224 680.5 J
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The Parker family drove a total of 180 miles on the road trip. This distance is 1.5 times the distance they drove on the first d
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Parker family drove 120 miles on the first day

Step-by-step explanation:

Given:

Total miles driven on the road trip= 180 miles

solution:

Lets assume the distance drove on the first day is x

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x=\frac{180}{1.5}

Hence, x = 120.

The distance travelled on the first day is 120 miles.

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2 years ago
Sean pays £10 for 24 chocolate bars. He sells all 24 chocolate bars for 50p each.
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Answer:

the percentage profit is 20%

Step-by-step explanation:

Given that

Sean paid  £10 for 24 chocolate bars

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we need to find out the percentage profit

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= 20%

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4 0
1 year ago
The quality control manager at a light bulb factory needs to estimate the mean life of a batch (population) of light bulbs. We a
Nadusha1986 [10]

Answer:

<em>a)95%  confidence intervals for the population mean of light bulbs in this batch</em>

(325.5 ,374.5)

b)

<em>The calculated value Z = 4 > 1.96 at 0.05 level of significance</em>

<em>Null hypothesis is rejected </em>

<em>The manufacturer has not right to take the average life of the light bulbs is 400 hours.</em>

Step-by-step explanation:

Given sample size n = 64

Given  mean of the sample x⁻ = 350

Standard deviation of the Population σ = 100 hours

The tabulated value Z₀.₉₅ = 1.96

<em>95%  confidence intervals for the population mean of light bulbs in this batch</em>

<em></em>(x^{-} - Z_{\frac{\alpha }{2} } \frac{S.D}{\sqrt{n} } , x^{-} + Z_{\frac{\alpha }{2} }\frac{S.D}{\sqrt{n} } )<em></em>

<em></em>(350 - 1.96\frac{100}{\sqrt{64} } , 350 + 1.96\frac{100}{\sqrt{64} } )<em></em>

(350 -24.5, 350 +24.5)

(325.5 ,374.5)

b)

<u><em>Explanation</em></u>:-

Given mean of the Population μ = 400

Given sample size n = 64

Given  mean of the sample x⁻ = 350

Standard deviation of the Population σ = 100 hours

<u><em>Null hypothesis</em></u> : H₀:The manufacturer has right to take the average life of the light bulbs is 400 hours.

μ = 400

<u><em>Alternative Hypothesis: H₁:</em></u> μ ≠400

<u><em>The test statistic </em></u>

Z = \frac{x^{-}-mean }{\frac{S.D}{\sqrt{n} } }

Z = \frac{350 -400}{\frac{100}{\sqrt{64} } }

|Z| = |-4|

The tabulated value   Z₀.₉₅ = 1.96

The calculated value Z = 4 > 1.96 at 0.05 level of significance

Null hypothesis is rejected.

<u><em>Conclusion:</em></u>-

The manufacturer has not right to take the average life of the light bulbs is 400 hours.

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The blade length is the radius of the circle formed by the area swept by the blades to the nearest square foot, what is the area
rewona [7]
Sorry i do not know wish i did 
3 0
1 year ago
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