What is 4.66666666667 as a fraction

6x+7y=4x+4y6x+7y=4x+4y6, x, plus, 7, y, equals, 4, x, plus, 4, y Complete the missing value in the solution to the equation. ((l

tia_tia [17]

Answer:

<h3>The missing value in the solution to the equation is 6.</h3><h3>So, the complete solution is (6, -4).</h3>

Step-by-step explanation:

Given:

6x+7y=4x+4y.

( ,-4)

Now, to complete the missing value in the solution to the equation.

As, the equation is:

$6x+7y=4x+4y$

And, the solution is:

$(x,y)=(\ \ ,-4)$

Now, solving the equation by putting the value of $y=-4$ :

$6x+7(-4)=4x+4(-4)\\\\6x+(-28)=4x+(-16)\\\\6x-28=4x-16\\\\$

Adding both sides by 28 we get:

$6x=4x+12$

Subtracting both sides by $4x$ we get:

$2x=12$

Dividing both sides by 2 we get:

$x=6.$

Thus, the solution to the equation is (6, -4).

Therefore, the missing value in the solution to the equation is 6.

4 0

1 year ago

1600 dollars is placed in an account with an annual interest rate of 5.25%. How much will be in the account after 25 years, to t

Andru [333]

Step-by-step explanation:

Exponential Functions:

y=ab^x

y=ab

x

a=\text{starting value = }1600

a=starting value = 1600

r=\text{rate = }5.25\% = 0.0525

r=rate = 5.25%=0.0525

\text{Exponential Growth:}

Exponential Growth:

b=1+r=1+0.0525=1.0525

\text{Write Exponential Function:}

Write Exponential Function:

y=1600(1.0525)^x

y=1600(1.0525)

x

Put it all together

\text{Plug in time for x:}

Plug in time for x:

y=1600(1.0525)^{25}

y=1600(1.0525)

25

y= 5750.0628984

y=5750.0628984

Evaluate

y\approx 5750.06

y≈5750.06

3 0

1 year ago

The volume of water in a tank is modeled by the function y = 1.15x3 – 0.1x2 + 2 where x is the number of minutes after the fauce

baherus [9]

Answer:

2

Step-by-step explanation:

in this context the y intercept represents the volume of water already in the tank

8 0

1 year ago

Read 2 more answers

A 3-gallon tub of ice cream yields about 90 scoops of ice cream. There are roughly 3785 cubic centimeters in 1 gallon. Determine

ASHA 777 [7]

Answer:

The radius of the scoop is r = 3.1 cm

Step-by-step explanation:

Since 3 gallons yields 90 scoops, and 1 gallon = 3785 cm³.

3 gallons = 3 × 3785 cm³ = 11355 cm³

So we have 11355 cm³ in 3 gallons which is also the volume of 90 scoops.

Since 90 scoops = 11355 cm³, then

1 scoop = 11355 cm³/90 = 126.2 cm³

Now, if each scoop is a sphere, the volume is given by V = 4πr³/3 where r is the radius of the scoop. Since we need to find the radius of the scoop, r, making r subject of the formula, we have

r = ∛(3V/4π)

Substituting V = 126.2 cm³, we have

r = ∛(3× 126.2 cm³/4π)

= ∛(378.6 cm³/12.57)

= ∛30.13 cm³

= 3.1 cm

So, the radius of the scoop is r = 3.1 cm

5 0

1 year ago

Suppose you are an expert on the fashion industry and wish to gather information to compare the amount earned per month by model

Ann [662]

Answer:

(1) The degrees of freedom for unequal variance test is (14, 11).

(2) The decision rule for the 0.01 significance level is;

If the value of our test statistics is less than the critical values of F at 0.01 level of significance, then we have insufficient evidence to reject our null hypothesis.

If the value of our test statistics is more than the critical values of F at 0.01 level of significance, then we have sufficient evidence to reject our null hypothesis.

(3) The value of the test statistic is 0.3796.

Step-by-step explanation:

We are given that you are an expert on the fashion industry and wish to gather information to compare the amount earned per month by models featuring Liz Claiborne's attire with those of Calvin Klein.

The following is the amount ($000) earned per month by a sample of 15 Claiborne models;

$3.5, $5.1, $5.2, $3.6, $5.0, $3.4, $5.3, $6.5, $4.8, $6.3, $5.8, $4.5, $6.3, $4.9, $4.2 .

The following is the amount ($000) earned by a sample of 12 Klein models;

$4.1, $2.5, $1.2, $3.5, $5.1, $2.3, $6.1, $1.2, $1.5, $1.3, $1.8, $2.1.

(1) As we know that for the unequal variance test, we use F-test. The degrees of freedom for the F-test is given by;

$\text{F}_(_n__1-1, n_2-1_)$

Here, $n_1$ = sample of 15 Claiborne models

$n_2$ = sample of 12 Klein models

So, the degrees of freedom = ( $n_1-1, n_2-1$ ) = (15 - 1, 12 - 1) = (14, 11)

(2) The decision rule for 0.01 significance level is given by;

If the value of our test statistics is less than the critical values of F at 0.01 level of significance, then we have insufficient evidence to reject our null hypothesis.

If the value of our test statistics is more than the critical values of F at 0.01 level of significance, then we have sufficient evidence to reject our null hypothesis.

(3) The test statistics that will be used here is F-test which is given by;

T.S. = $\frac{s_1^{2} }{s_2^{2} } \times \frac{\sigma_2^{2} }{\sigma_1^{2} }$ ~ $\text{F}_(_n__1-1, n_2-1_)$

where, $s_1^{2}$ = sample variance of the Claiborne models data = $\frac{\sum (X_i-\bar X)^{2} }{n_1-1}$ = 1.007

$s_2^{2}$ = sample variance of the Klein models data = $\frac{\sum (X_i-\bar X)^{2} }{n_2-1}$ = 2.653

So, the test statistics = $\frac{1.007}{2.653 } \times 1$ ~ $\text{F}_(_1_4,_1_1_)$

= 0.3796

Hence, the value of the test statistic is 0.3796.

3 0

1 year ago