There are 36 inches in a yard, so that is the denominator being asked for.
1/4 yard = 9/36 yards
5/6 yard = 30/36 yards
Answer:
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Answer:
W=0.8333*t
2.917 ft³
Step-by-step explanation:
At time t=3, there is 2.5 ft³ of water in the tub
Finding the relation will be;
3=2.5
1=?
Rate=0.8333 ft³/min
W=0.8333 ft³ / min
W=0.8333*t
At t=3.5 will be;
1 min = 0.8333
3.5 min =?
Apply cross-production
3.5*0.8333 =2.917 ft³
Answer:
The <em>p</em>-value of the test is 0.0512.
Step-by-step explanation:
The <em>p</em>-value of a test is well-defined as per the probability, [under the null hypothesis (H₀)], of attaining a result equivalent to or more extreme than what was the truly observed value of the test statistic.
In this case the output of the t-test_ind method from scipy module is provided as follows:
Output = (-1.99, 0.0512)
The first value within the parentheses is the test statistic value.
So the test statistic value is, -1.99.
And the second value within the parentheses is the <em>p</em>-value of the test.
So the <em>p</em>-value of the test is 0.0512.