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Alexxandr [17]
2 years ago
12

What is the volume V of a sample of 3.10 mol of copper? The atomic mass of copper (Cu) is 63.5 g/mol, and the density of copper

is 8.92×103kg/m3. Express your answer in cubic centimeters to 3 significant figures.
Chemistry
1 answer:
alekssr [168]2 years ago
5 0

Answer:

4.50 x 10^7 cm3.

Explanation:

Given:

Number of moles of Copper = 3.10 mol.

Atomic mass of copper = 63.5 g/mol

Density of copper = 8.92 × 10^3 kg/m^3

Mass of copper = number of moles * atomic mass of copper

= 3.10 * 63.5

= 196.85 g of copper.

Density = mass/volume

Volume = 8.92 × 10^3 / 196.86

= 45 m3

Converting m3 to cm3,

Remember,

1 m = 100 cm,

1 m3 = 1000000 cm3

Therefore,

45 m3 = 45 * 1000000

= 4.5 x 10^7 cm3.

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What is net ionic equation borax hydrolysis?
deff fn [24]
The net ionic equation of borax hydrolysis would be:

 <span>Na2B4O7 + 7H2O-----------------> 2 NaOH + 4 H3BO3
</span>
Wherein 2 moles of sodium hydroxide and 4 moles of boric acid are produced by the hydrolysis.
I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!
7 0
2 years ago
Determine the empirical formula for compounds that have the following analyses: a. 66.0% barium and 34.0% chlorine b. 80.38% bis
almond37 [142]

Answer: a) BaCl_2

b)  BiO_3H_3

Explanation:

If percentage are given then we are taking total mass is 100 grams.

So, the mass of each element is equal to the percentage given.

a) Mass of Ba= 66.06 g

Mass of Cl = 34.0 g

Step 1 : convert given masses into moles.

Moles of Ba =\frac{\text{ given mass of ba}}{\text{ molar mass of Ba}}= \frac{66.06g}{137g/mole}=0.48moles

Moles of Cl = \frac{\text{ given mass of Cl}}{\text{ molar mass of Cl}}= \frac{34g}{35.5g/mole}=0.96moles[/tex]

Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.

For Ba = \frac{0.48}{0.48}=1

For O =\frac{0.96}{0.48}=2

The ratio of Ba: Cl= 1:2

Hence the empirical formula is BaCl_2

b) Mass of Bi= 80.38 g

Mass of O= 18.46 g

Mass of H = 1.16 g

Step 1 : convert given masses into moles.

Moles of Bi =\frac{\text{ given mass of ba}}{\text{ molar mass of Ba}}= \frac{80.38g}{209g/mole}=0.38moles

Moles of O= \frac{\text{ given mass of O}}{\text{ molar mass of O}}= \frac{18.46g}{16g/mole}=1.15moles

Moles of H=\frac{\text{ given mass of H}}{\text{ molar mass of H}}= \frac{1.16g}{1g/mole}=1.16moles

Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.

For Bi= \frac{0.38}{0.38}=1

For O =\frac{1.15}{0.38}=3

For H=\frac{1.16}{0.38}=3

The ratio of Bi: O: H= 1:3: 3

Hence the empirical formula is BiO_3H_3

6 0
2 years ago
Which element is used in light bulbs as a filament
mojhsa [17]
<span>The element that is used in light bulbs as a filament is tungsten - this is almost always the case in halogen and incandescent bulbs. Tungsten is chosen for this purpose because of the fact it can withstand temperatures of up to 4,500 degrees, as well as being incredibly flexible.</span>
8 0
2 years ago
A. Use average bond energies together with the standard enthalpy of formation of C(g) (718.4 kJ/mol ) to estimate the standard e
Nana76 [90]

Answer:

a. 278.4kJ/mol

b. due to resonance, some energy are released

Explanation:

5 0
2 years ago
What is the volume (in ml) of a 12.9 g piece of metal with a density of 7.25 g/cm3?
Leto [7]
Hey there:

1 cm³ = 1 mL

D = m  / V

7.25 = 12.9 / V

V = 12.9 / 7.25

V = 1.779 cm³
6 0
2 years ago
Read 2 more answers
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