Answer:
Example of qualitative variable: hair colour.
Example of discrete quantitative variable: age.
a) Qualitative data displays are pie charts, histograms
b) Quantitative data displays are scatter and line graphs.
Step-by-step explanation:
A qualitative variable expresses a non-numerical quality of an object or person. For example, hair colour (brown, blonde, red...) or eye colour (green, blue, brown...).
A quantitative variable is a numerical value. For example, temperature (100 K, 2000 K...) or age (12 years, 20 years...).
A discrete quantitative variable can be obtained by counting, like the number of cars in a road. This is plotted in scatter graphs. For continuous variable, it can be obtained by measuring, like the height of your family members. This is plotted in line graphs.
- Pie charts: is a circular graphic that shows the statistics or number of people or objects with certain characteristics. For example, how many people have brown hair, how many are blonde and how many are redheaded.
- Histograms: they show vertical bars associated with the qualitative variable in the x-axis and the number of objects or people with that characteristic in the y-axis.
- Scatter: it is a graph with x and y axis and using Cartesian coordinates. Since it is for quatities, numbers can be represented as points.
- Line graphs: it is basically the same as a scatter plot but in this case the points can be joined by a line because the quantities are connected or are continuous.
Answer:
The initial value is 3.
The range is y greater than 0.
The simplified base is 8.
Step-by-step explanation:
The given function is 
......... (1)
Therefore, the initial value of the function at x = 0 is 
Now, the domain can be any real value, since for all real value of x, y exists.
But, for no value of x the function has value < 0.
Therefore, y greater than 0 is the range of the function f(x).
Now, simplifying the equation (1) we will have
Therefore, the simplified base is 8. (Answer)
Answer: 
Step-by-step explanation:
<h3>
The complete exercise is: " A theatre has the capacity to seat people across two levels, the Circle, and the stalls. The ratio of the number of seats in the circle to a number of seats in the stalls is 2:5. Last Friday, the audience occupied all the 528 seats in the circle and 
of the seats in the stalls. What is the percentage of occupancy of the theatre last Friday?"</h3>
Let be "s" the total number of seats in the Stalls.
The problem says that the ratio of the number of seats in the Circle to the number of seats in the Stalls is 
.
Since the number of seats that were occupied last Friday was 528 seats, we can set up the following proportion:
Solving for "s", we get:
So the sum of the number of seats in the Circle and the number of seats in the Stalls, is:
We know that of the seats in the Stalls were occupied. Then, the number of seat in the Stalls that were occupied is:
Therefore, the total number of seats that were occupied las Friday is:
Knowing this, we can set up the following proportion, where "p" is the the percentage of occupancy of the theatre last Friday:
Solving for "p", we get:
1. You have the following information given in the problem above:
- Ella mixed<span> two kinds of candy the price of which was $2 and $4 per pound.
- Ella got a 10-lb mix of candy, which cost $2.90 per pound.
</span>
2. Therefore, let's call:
x: pounds of the first kind of candy.
y: pounds of the second kind of candy.
3. Then, you have:
2x+4(10-x)=(2.90)(10)
4. When you clear x, you obtain:
2x+40-4x=29
-2x=29-40
x=-11/-2
x=5.5 pounds
x+y=10
y=10-x
y=10-5.5
y=4.5 pounds
so, 13 of the 20 tables have 6 chairs each.
that means, the remaining 7 tables, have 4 chairs each.
13 * 6 = 78 chairs total for those 13 tables.
7 * 4 = 28 chairs total for the remaining 7 tables.
78 + 28, that's how many.
