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lord [1]
2 years ago
7

A 0.350g sample of a large biomolecule was dissolved in 15.0g of benzene, and the freezing point depression was determined to be

0.262oC. Calculate the molar mass of the biomolecule.
Chemistry
1 answer:
hichkok12 [17]2 years ago
5 0

Answer:

The molar mass of the biomolecule is 455.73 g/mol

Explanation:

∆T = m × Kf

m (molality) = ∆T/Kf

∆T = 0.262 °C, Kf of benzene = 5.12 °C/m

m = 0.262/5.12 = 0.0512 mol/kg

Molecular mass of the biomolecule = mass of biomolecule ÷ (molality × mass of benzene in kilograms) = 0.350 ÷ (0.0512 × 15/1000) = 0.350 ÷ 0.000768 = 455.73 g/mol

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<span>Density is a value for mass, such as kg, divided by a value for volume, such as m3. Density is a physical property of a substance that represents the mass of that substance per unit volume. We calculate as follows:

PV = nRT
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A toy car is placed at 0 on a number line. It moves 9 cm to the left, then 4 cm to the right, and then 6 cm to the left. What is
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The combustion of propane occurs when propane interacts with oxygen gas to produce water and carbon dioxide in the following rea
gtnhenbr [62]

Answer:

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<u>1) Data:</u>

a) n = 2 moles

b) T = 373 K

c) V = 2.5 liter

d) P = ?

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You need to calculate the pressure of the propane gas in the mixture before reacting. So, you can apply the partial pressure principle which states that each gas exerts a pressure as if it occupies the entire volume.

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