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BaLLatris [955]
2 years ago
6

The combustion of propane occurs when propane interacts with oxygen gas to produce water and carbon dioxide in the following rea

ction:
C3H8 (g) + 5O2 (g) → 3CO2 (g) + 4H2O(l)


If 2 moles of propane C3H8 (g) react at 373 K in a volume of 2.5 L, what is the pressure in the cylinder from the C3H8 (g)?
Chemistry
1 answer:
gtnhenbr [62]2 years ago
5 0

Answer:

  • 20 atm

Explanation:

<u>1) Data:</u>

a) n = 2 moles

b) T = 373 K

c) V = 2.5 liter

d) P = ?

<u>2) Chemical principles and formula</u>

You need to calculate the pressure of the propane gas in the mixture before reacting. So, you can apply the partial pressure principle which states that each gas exerts a pressure as if it occupies the entire volume.

Thus, you just have to use the ideal gas equation: PV = nRT

<u>3) Solution:</u>

  • PV = nRT ⇒ P = nRT / V

P = 2 mol × 0.08206 atm-liter /K-mol × 373K / 2.5 liter = 24.5 atm

Since the number of moles are reported with one significant figure, you must round your answer to one significant figure, and that is 20 atm (20 is closer to 24.5 than to 30).

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Answer:

Work= Fs

Work 30x2

Work 60 J

Explanation:

A lot of work

3 0
2 years ago
Which phrase describes the molecular structure and properties of two solid forms of carbon, diamond and graphite?(1) the same mo
vagabundo [1.1K]
I think the answer is (4) different molecular structures and different properties. Both structure are crystal. The structure of graphite is organized in layers. And structure of diamond is a strong network of atoms. Also due to the different structures, they have different properties.
4 0
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In Part B the given conditions were 1.00 mol of argon in a 0.500-L container at 27.0 ∘C . You identified that the ideal pressure
dimaraw [331]

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Ideal pressure (true value) = 49.3 atm

Real pressure (measured value) = 47.3 atm

The formula used to calculate percent difference is :

Percent difference = \frac{\text{True value - Measured value}}{\text{True value}} \times 100

Percent difference = \frac{(49.3- 47.3)atm}{49.3atm}\times 100

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Therefore, the percent difference between the ideal and real gas is, 4.06 %.

4 0
2 years ago
Sulfurous acid, h2so3, breaks down into water (h2o) and sulfur dioxide (so2). if only one molecule of sulfurous acid was involve
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Explanation:

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Now, number of atoms on reactant side are as follows.

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Thus, we can conclude that there is one sulfur atom in the products.

6 0
2 years ago
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= 2.2 x 10⁻⁵

The answer is A.
7 0
2 years ago
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