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2 years ago

How many molecules are present in 0.336 mol of acetylene (C2H2)?

Chemistry

1 answer:

Elena L [17]2 years ago

7 0

Answer:

The answer is 26.03728. We assume you are converting between grams C2H2 and mole. You can view more details on each measurement unit: molecular weight of C2H2 or mol This compound is also known as Acetylene. The SI base unit for amount of substance is the mole.

Explanation:

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A student measured the mass of some sodium chloride for a lab. the lab called for 6.25 g (the accurate measurement ) , but the s

Yuri [45]

Answer:

The answer is

$\huge 4\%$

Explanation:

The percentage error of a certain measurement can be found by using the formula

$P(\%) = \frac{error}{actual \: \: number} \times 100\% \\$

From the question

actual mass = 6.25 g

error = 6.25 - 6 = 0.25

So we have

$p(\%) = \frac{0.25}{6.25} \times 100$

We have the final answer as

Hope this helps you

3 0

2 years ago

A student is given a sample of a blue copper sulfate hydrate. He weighs the sample in a dry covered porcelain crucible and got a

Nata [24]

Answer:

There are present 5,5668 moles of water per mole of CuSO₄.

Explanation:

The mass of CuSO₄ anhydrous is:

23,403g - 22,652g = 0,751g.

mass of crucible+lid+CuSO₄ - mass of crucible+lid

As molar mass of CuSO₄ is 159,609g/mol. The moles are:

0,751g × $\frac{1mol}{159,609g}$ = 4,7052x10⁻³ moles CuSO₄

Now, the mass of water present in the initial sample is:

23,875g - 0,751g - 22,652g = 0,472g.

mass of crucible+lid+CuSO₄hydrate - CuSO₄ - mass of crucible+lid

As molar mass of H₂O is 18,02g/mol. The moles are:

0,472g × $\frac{1mol}{18,02g}$ = 2,6193x10⁻² moles H₂O

The ratio of moles H₂O:CuSO₄ is:

2,6193x10⁻² moles H₂O / 4,7052x10⁻³ moles CuSO₄ = 5,5668

That means that you have <em>5,5668 moles of water per mole of CuSO₄.</em>

I hope it helps!

5 0

2 years ago

If a 1.00 mL sample of the reaction mixture for the equilibrium constant experiment required 32.40 mL of 0.258 M NaOH to titrate

andrey2020 [161]

Answer:

The concentration of acetic acid is 8.36 M

Explanation:

Step 1: Data given

Volume of acetic acid = 1.00 mL = 0.001 L

Volume of NaOH = 32.40 mL = 0.03240 L

Molarity of NaOH = 0.258 M

Step 2: The balanced equation

CH3COOH + NaOH → CH3COONa + H2O

Step 3: Calculate the concentration of the acetic acid

b*Ca*Va = a*Cb*Vb

⇒with b = the coefficient of NaOH = 1

⇒with Ca = the concentration of CH3COOH = TO BE DETERMINED

⇒with Va = the volume of CH3COOH = 1.00 mL = 0.001L

⇒with a = the coefficient of CH3COOH = 1

⇒with Cb = the concentration of NaOH = 0.258 M

⇒with Vb = the volume of NaOH = 32.40 mL = 0.03240 L

Ca * 0.001 L = 0.258 * 0.03240

Ca = 8.36 M

The concentration of acetic acid is 8.36 M

6 0

2 years ago

If one has a solution of 0.10 m silver nitrate and it is diluted by a factor of two, what is the new concentration

Angelina_Jolie [31]

Diluted by a factor of two means that we double the volume of the solution by adding an equal volume of the water.
if we diluted it by a factor of one so the new concentration = 0.1/2=0.05 M and diluted by a factor of two so, the new concentration will be 0.05/2 = 0.025 M

7 0

2 years ago

While looking at xenon (Xe) on the periodic table, a student needs to find an element with a smaller atomic mass in the same gro

zvonat [6]

Answer is: directly up.

Neon (Ne) is noble gas with atomic number 10 and atomic mass around 20.

1) directly up is noble gas helium (He) with atomic mass around 4.

2) directly down is noble gas argon (Ar) with atomic mass around 40.

3) directly to the left is florine (F), with smaller atomic mass, but also from different group.

4) directly to the right there no elements, because noble gases are far right in 18. group of Periodic table.

3 0

2 years ago

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