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Ann [662]
2 years ago
7

After being thoroughly stirred at 10.°C, which mixture is heterogenous?(1) 25.0 g of KCl and 100. g of H2O

Chemistry
1 answer:
VladimirAG [237]2 years ago
5 0
The answer is (2) KNO3. This depends on the solubility of these four compounds at 10℃. After checking the table, you can find that only KNO3 is less than 25.0 g.
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Let us differentiate accuracy from precision. Accuracy is the nearness of the measured value to the true or exact value. On the other hand, precision is the nearness of the measured values between each other. So, for precision, select the student in which the measured values are very near to each other. That would be Student III. Now, for accuracy, let's find the average for each student.

Student I: (<span>8.72g+8.74g+8.70g)/3 = 8.72 g
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From the given results, the accurate one would be Students I and II. So, we make a compromise. Even though Student III is precise, it is not accurate. If you compare between Students I and II, the more precise data would be Student I. Therefore, the answer is Student I.</span>
6 0
2 years ago
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Elements that do not have full outer electron shells will donate, share, or take electrons from other atoms. Choose the items th
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it´s actually Lithium and fluorine / Magnesium and Chlorine / Beryllium and Nitrogen

8 0
2 years ago
Based on the values you obtained for δh∘rxn, which of the reactions would you expect to be thermodynamically favorable and which
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Following reactions are involved in present reaction
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2) </span><span>2Fe(s)     +     2Na+(aq)      →        Fe2+(aq)      +       2Na(s)     +   392.3kJ
</span>3)  <span>2K(s)     +      2H2O(l)      →      2KOH(aq)       +H2(g)       −393.1kJ

In above reaction, reaction 1 and 3 has negative value of </span>δh∘f, while reaction 2 has posiyive value of <span>δh∘f. As per the sign convention positive sign indicates that heat is given out during the reaction, while negative sign indicates heat is to be supplied for reaction to occur. In alternative words, product formed in reaction 2 is stable as compared to reactant. Hence, it is thermodynamically favorable. </span>
7 0
2 years ago
A certain isotope x2+ contains 48 electrons and 75 neutrons. what is the mass number for this element?
gulaghasi [49]
The most important identity of an element is its atomic number or number of protons. Electrons and neutrons may vary, but protons stay constant. To start with, when an element is neutral, the number of protons and electrons are equal. When the isotope is a positive ion, that means that the element gives away 2 electrons. So, if the electrons is 48, then that means it was originally 48 - 2 = 46 electrons. From the periodic table, element 46 is Palladium (Pd).
8 0
2 years ago
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Be sure to answer all parts. Consider the formation of ammonia in two experiments. (a) To a 1.00−L container at 727°C, 1.30 mol
Sonbull [250]

<u>Answer:</u> The value of K_c for 2NH_3(g)\rightleftharpoons N_2(g)+3H_2(g) reaction is 5.13\times 10^2

<u>Explanation:</u>

We are given:

Initial moles of nitrogen gas = 1.30 moles

Initial moles of hydrogen gas = 1.65 moles

Equilibrium moles of ammonia = 0.100 moles

Volume of the container = 1.00 L

For the given chemical equation:

                N_2(g)+3H_2(g)\rightleftharpoons 2NH_3(g)

<u>Initial:</u>            1.30       1.65

<u>At eqllm:</u>       1.30-x    1.65-3x             2x

Evaluating the value of 'x'

\Rightarrow 2x=0.100\\\\\Rightarrow x=0.050mol

The expression of K_c for above equation follows:

K_c=\frac{[NH_3]^2}{[N_2]\times [H_2]^3}

Equilibrium moles of nitrogen gas = (1.30-x)=(1.30-0.05)=1.25mol

Equilibrium moles of hydrogen gas = (1.65-x)=(1.65-0.05)=1.60mol

Putting values in above expression, we get:

K_c=\frac{(0.100)^2}{1.25\times (1.60)^3}\\\\K_c=1.95\times 10^{-3}

Calculating the K_c' for the given chemical equation:

2NH_3(g)\rightleftharpoons N_2(g)+3H_2(g)

K_c'=\frac{1}{K_c}\\\\K_c'=\frac{1}{1.95\times 10^{-3}}=5.13\times 10^2

Hence, the value of K_c for 2NH_3(g)\rightleftharpoons N_2(g)+3H_2(g) reaction is 5.13\times 10^2

8 0
2 years ago
Read 2 more answers
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