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torisob [31]
2 years ago
7

A compound that weighs 40.8 g contains 23.6 g Sb and 17.2 g F. What is the percent composition of antimony?

Chemistry
1 answer:
Rus_ich [418]2 years ago
4 0

<u>Answer:</u> The percent antimony in the compound is 57.8 %

<u>Explanation:</u>

To calculate the percentage composition of antimony in compound, we use the equation:

\%\text{ composition of antimony}=\frac{\text{Mass of chlorine}}{\text{Mass of sample}}\times 100

Mass of compound = 40.8 g

Mass of antimony = 23.6 g

Putting values in above equation, we get:

\%\text{ composition of antimony}=\frac{23.6g}{40.8g}\times 100=57.8\%

Hence, the percent antimony in the compound is 57.8 %

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