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sashaice [31]
2 years ago
12

A monkey has filled in a 3 × 3 grid with the numbers 1, 2, . . . , 9. A cat writes down the three numbers obtained by multiplyin

g the numbers in each horizontal row. A dog writes down the three numbers obtained by multiplying the numbers in each vertical column. Can the monkey fill in the grid in such a way that the cat and dog obtain the same set of three numbers? What if the monkey writes the numbers 1, 2, . . . , 25 in a 5×5 grid? Or 1, 2, . . . , 121 in a 11 × 11 grid? Can you find any conditions on n that guarantee that it is possible or any conditions that guarantee that it is impossible for the monkey to write the numbers 1, 2, . . . , n2 in an n × n grid so that the cat and the dog obtain the same set of numbers?
Mathematics
1 answer:
Juliette [100K]2 years ago
8 0

Answer:

6

Step-by-step explanation:

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The annual interest rate of Marta's savings account is 7.2% in a simple interest is calculated quarterly. What is the periodic i
kkurt [141]
1. You have the following information:
 
 -The annual interest rate <span>is 7.2%.
 - The </span><span>simple interest is calculated quarterly.
 
 2. Then, to solve this exercise and calculate the </span><span>periodic interest rate of Marta's Account, you only have to divide the annual interest rate (7.2%) by 1/4 year. So, you have:
</span> 
 =(7.2%)(1/4)
 =(7.2%)/4
 =1.8%
 
 <span>What is the periodic interest rate of Marta's Account?
 
 The answer is: </span>1.8%
7 0
2 years ago
A survey found that 89% of a random sample of 1024 American adults approved of cloning endangered animals. Find the margin of er
Kobotan [32]

Answer:

The margin of error for the survey is 0.016

Step-by-step explanation:

We are given the following in the question:

Sample size, n = 1024

Sample proportion:

\hat{p} = 89\% = 0.89

We have to find the margin of error associated with a 90% Confidence interval.

Formula for margin of error:

z_{stat}\times \sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}

z_{critical}\text{ at}~\alpha_{0.10} = 1.64

Putting the values, we get:

M.E = 1.64\times (\sqrt{\dfrac{0.89(1-0.89)}{1024}})\\\\M.E=0.016

Thus, the margin of error for the survey is 0.016

3 0
2 years ago
A stereo manufacturer makes three types of stereo systems, I, II, and III, with profits of $20, $30, and $40, respectively. No m
romanna [79]
So,

1. Type I profits $20
2. Type II profits $30
3. Type III profits $40
4. I/day < 100
5. Type I needs 5 hrs.
6. Type II needs 10 hrs.
7. Type III needs 15 hrs.
8. Total hrs. available: 2000 hrs.

Every +5 hrs. spent yields an extra $10.
If we use 500 hrs. to make 100 Type I stereos, we will profit $2000.
If we use 500 hrs. to make 50 Type II stereos, we will profit $1500.
If we use 495 hrs. to make 33 Type III stereos, we will profit $1320.

We should use the first 500 hrs. to make Type I stereos.
We should use the last 1500 hrs. to make Type II stereos.

$2000 + $4500 = x
$6500 = x

There must be 100 Type I stereos made along with 150 Type II stereos made.
4 0
2 years ago
Sarah can bicycle a loop around the north part of Lake Washington in 2 hours and 30 minutes. If she could increase her average s
netineya [11]

Answer:

The length of the loop is approximately 49.58 km.

Step-by-step explanation:

Given:

Time required to ride bicycle in loop = 2 hours and 30 mins

Now we know that;

60 mins = 1 hour

30 mins =0.5 hour

so 2 hour and 30 mins = 2+0.5 = 2.5\ hrs

∴ Time required to ride bicycle in loop = 2.5 hrs

Let the speed at which she is riding the bicycle be 's'.

and let Total distance of the loop be 'd'

Now we know that;

Distance is given by speed multiplied by time.

framing in equation form we get;

d =2.5s \ \ \ \ equation \ 1

Now Given:

If she increase the speed by 1 km/hr, it would reduce her time around the loop by 7 minutes.

Hence we can say;

Speed =s+1

Also time will be reduce to 7 mins.

7 mins  =0.12 hrs

Now time = 2.5-0.12 =2.38

Again Distance is given by speed multiplied by time.

framing in equation form we get;

d =2.38(s+1) \ \ \ \ equation \ 2

Now distance is same for both so we will calculate the speed by equating the equations.

2.5s = 2.38(s+1)\\\\2.5s=2.38s+2.38\\\\2.5s-2.38s =2.38\\\\0.12s= 2.38\\\\s =\frac{2.38}{0.12} \approx 19.83\ km/hr

Now Speed = 19.83 km/hr

Length of the loop (d) = 19.83\times 2.5 = 49.58 \ km

Hence the length of the loop is approximately 49.58 km.

7 0
2 years ago
Michaela’s class used a spinner that has 6 spaces of equal area in which the arrow can land. The areas are numbered 1, 2, 3, 4,
diamong [38]

The number of times the spinner landed on a space numbered greater than 4 = 167

Step-by-step explanation:

Step 1 :

Given,

Number of equal area spaces in the spinner = 6

Number of times the spinner was spun = 500

We need to find  the number of times the spinner landed on a space numbered greater than 4

Step 2 :

Total number of outcome = 6

Favorable outcomes are = Numbers greater than 4 = 5,6

Total number of favorable outcome = 2

Therefore Probability that the spinner will land on a number that is greater than 4 is \frac{2}{6} = \frac{1}{3}

The number of times that the spinner landed on a space numbered greater than 4 = 500 × \frac{1}{3} = 166.67 = 167 (rounded off to the nearest integer)

Step 3 :

Answer :

The number of times the spinner landed on a space numbered greater than 4 = 167

4 0
2 years ago
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