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Lerok [7]
2 years ago
14

Consider a differential equation of the form y′=f(αt+βy+γ)y′=f(αt+βy+γ), where α,βα,β, and γγ are constants. Use the change of v

ariable z=αt+βy+γz=αt+βy+γ to rewrite the differential equation as a separable equation of the form z′=g(z)z′=g(z).
Mathematics
1 answer:
Dmitrij [34]2 years ago
5 0

The question is:

Consider a differential equation of the form

y′ = f(αt + βy + γ),

where α,β, and γ are constants. Use the change of variable

z = αt + βy + γz

to rewrite the differential equation as a separable equation of the form z′ = g(z).

Answer:

The equation

y′ = f(αt + βy + γ)

can be written as

dy/dt = f(αt + βy + γ).

We want to rewrite this differential equation is the form

z' = g(z), that is dz/dt = g(z).

First, note that

dz/dt = (dz/dy).(dy/dt)...................(1)

Using the substitution

z = αt + βy + γ

as required,

dz/dy = β ..........................................(2)

dy/dt = f(αt + βy + γ) = f(z) ............(3)

From (2) and (3)

dz/dt = β.f(z) = g(z)

So,

z' = g(z)

Where g(z) = βf(z).

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Segment AB falls on line 6x + 3y = 12. Segment CD falls on line 4x + 2y = 8. What is true about segments AB and CD? They are par
nikklg [1K]

Answer:

They are parallel because they have the same slope of −2.

Step-by-step explanation:

got it right on the test, it is correct

6 0
2 years ago
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A company receives shipments of a component used in the manufacture of a component for a high-end acoustic speaker system. When
Tanya [424]

Answer:

ME= 2.33*\sqrt{\frac{0.096*(1-0.096)}{250}}= 0.0434

Step-by-step explanation:

For this case we have a sample size of n = 250 units and in this sample they found that 24 units failed one or more of the tests.

We are interested in the proportion of units that fail to meet the company's specifications, and we can estimate this with:

\hat p = \frac{24}{250}= 0.096

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

The confidence interval for a proportion is given by this formula  

\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}  

For the 98% confidence interval the value of \alpha=1-0.98=0.02 and \alpha/2=0.01, with that value we can find the quantile required for the interval in the normal standard distribution.  

z_{\alpha/2}=2.33  

And the margin of error would be:

ME= 2.33*\sqrt{\frac{0.096*(1-0.096)}{250}}= 0.0434

4 0
2 years ago
Which inequality is true if p= 3.4?
BigorU [14]

Answer:

None of the equations are true for p = 3.4

Step-by-step explanation:

In order for the inequality to be valid we need to apply the value for p and check wether or not it is true. We gonna do for each of the following:

A. 3p < 10.2

3*3.4 < 10.2

10.2 < 10.2

Not true, since the left side is equal to the right side and not less.

B. 13.6 < 3.9p

13.6 < 3.9*3.4

13.6 < 13.26

Not true since 13.6 is greater than 13.26

C. 5p > 17.1

5*3.4 > 17.1

17 > 17.1

Not true since 17 is less than 17.1

D. 8.5 > 2.5p

8.5 > 2.5*3.4

8.5 > 8.5

Not true since the left side is equal to the right side.

7 0
2 years ago
The area of Norway is 24% more than the area of Colorado so Norway's area is-------% of Colorado's area
zhenek [66]
Possibly 124%.........
8 0
2 years ago
last night, julie's pet hamster zoe kept julie awake for at least an hour running on her exercise wheel and scratching at the co
borishaifa [10]

Answer: x+y\geq 1, x>\frac{1}{4} ,  x\geq 2y and y\geq 0

Step-by-step explanation:

Here,  x represents the number of hours Zoe spent running on her wheel and y represents the number of hours spent scratching her cage.

Julie was awoke for at least an hour running on her exercise wheel and scratching the of her cage.

⇒ x+y\geq 1

She ran on her wheel at least twice as long as she scratched at the corners of her cage.

⇒ x\geq 2y

Also, She spent more than 1/4 hour running on her wheel.

⇒ x>\frac{1}{4}

And, we know that number of hours can not be negative.

⇒  y\geq 0

Therefore, the complete system of inequality which shows the given situation is,

x+y\geq 1, x>\frac{1}{4} and x\geq 2y, y\geq 0

Note: the feasible region ( covered by the given system) is shown in the below graph.


6 0
2 years ago
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