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Allisa [31]
1 year ago
11

2.10-kg box is moving to the right with speed 8.50 m>s on a horizontal, frictionless surface. At t = 0 a horizontal force is

applied to the box. The force is directed to the left and has magnitude F1t2 = 16.00 N>s22t2. (a) What distance does the box move from its position at t = 0 before its speed is reduced to zero? (b) If the force continues to be applied, what is the speed of the box at t = 3.00 s?

Physics
2 answers:
larisa86 [58]1 year ago
8 0

Explanation:

Below is an attachment containing the solution.

vodka [1.7K]1 year ago
4 0

Answer:

a) the distance moved by the object is 14m

b) the speed of the box at 3.00s is - 18.5m/s

The negative sign in the answer indicates that the speed of the box is in opposite direction. Therefore, the direction of the box is towards left.

Explanation:

see the attached file

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Elina [12.6K]

Answer:

10.791 m/s

5.93505 m

Explanation:

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t_i = Initial time

g = Acceleration due to gravity = 9.81 m/s²

From the momentum principle we have

\Delta P=F\Delta t

Force

F=mg

So,

m(v_f-v_i)=mg(t_f-t_i)\\\Rightarrow v_i=v_f-g(t_f-t_i)\\\Rightarrow v_i=0-(-9.81)(1.1-0)\\\Rightarrow v_i=10.791\ m/s

The speed that the ball had just after it left the hand is 10.791 m/s

As the energy of the system is conserved

K_i=U\\\Rightarrow \dfrac{1}{2}mv_i^2=mgh\\\Rightarrow h=\dfrac{v_i^2}{2g}\\\Rightarrow h=\dfrac{10.791^2}{2\times 9.81}\\\Rightarrow h=5.93505\ m

The maximum height above your hand reached by the ball is 5.93505 m

5 0
2 years ago
Bianca is standing at x =600m. Firecracker 1, at the origin, and firecracker 2, at x =900m, explode simultaneously. The flash fr
agasfer [191]

Answer:3 \mu s

Explanation:

Given

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time taken to reach Bianca eyes is

t=\frac{600}{speed\ of\ light}

t=\frac{600}{3\times 10^8}

t=2\times 10^{-6} s

t=2 \mu s

i.e. Cracker exploded at t=2\mu s because it is observed at t=4\mu s

Time taken by second cracker flash to reach Bianca eyes

t_2=\frac{300}{3\times 10^8}

t_2=10^{-6}

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Which changes in an electric motor will make the motor stronger? Check all that apply. using a stronger permanent magnet using a
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4 0
1 year ago
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A flat circular loop of wire of radius 0.50 m that is carrying a 2.0-A current is in a uniform magnetic field of 0.30 T. What is
Luba_88 [7]

Answer:

The magnitude of the magnetic torque on the loop when the plane of its area is perpendicular to the magnetic field is 0.4713 J

Explanation:

Given;

radius of the circular loop of wire = 0.5 m

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Therefore, the magnitude of the magnetic torque on the loop when the plane of its area is perpendicular to the magnetic field is 0.4713 J

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Newton's laws A force cannot act  alone is the THIRD LAW!

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