Answer:
X and Z
Explanation:
Conduction occurs through direct physical contact. Heat transferred from the pot to the handle, and from the handle to the hand, are both examples of conduction.
2.10-kg box is moving to the right with speed 8.50 m>s on a horizontal, frictionless surface. At t = 0 a horizontal force is
applied to the box. The force is directed to the left and has magnitude F1t2 = 16.00 N>s22t2. (a) What distance does the box move from its position at t = 0 before its speed is reduced to zero? (b) If the force continues to be applied, what is the speed of the box at t = 3.00 s?
2 answers:
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Answer:
Explanation:
The momentum of the neutron before and after the decay is the same since there's no external force.
#The neutron is initially at rest, so after the decay:
#After decay, the proton has +ve direction with a velocity while the electron moves in a negative direction with a velocity
Therefore:
Let the energy released during the decay be Q:
Hence,Kp/Ktot is 5.444x10^(-4)
Answer:
The magnitude of the electric field at a point equidistant from the lines is
Explanation:
Given that,
Positive charge = 24.00 μC/m
Distance = 4.10 m
We need to calculate the angle
Using formula of angle
We need to calculate the magnitude of the electric field at a point equidistant from the lines
Using formula of electric field
Put the value into the formula
Hence, The magnitude of the electric field at a point equidistant from the lines is
