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sweet [91]
2 years ago
13

A car rounds an unbanked curve of radius 65 m. If the coefficient of static friction between the road and car is 0.70, what is t

he maximum speed at which the car can traverse the curve without slipping?
Physics
1 answer:
True [87]2 years ago
3 0

Answer:

v = 21.127 m/s

Explanation:

Let's start off with the equation for centrifugal force:

F = m*v^2 / r

This force has to be equal to the force of friction which is:

F=u * R   (where u = coefficient of friction and R = mass * gravity )

Assumption: The car is travelling on horizontal ground

We can set the above equations equal to one another to get:

(m*v^2)/r = u * (m * 9.81)

here u = 0.7

r = 65

and mass cancels out on each side

Solving for v, we get:

v = 21.127 m/s

You might be interested in
Does a fish appear closer or farther from a person wearing swim goggles with an air pocket in front of their eyes than the fish
Sunny_sXe [5.5K]

Answer:

In this case, the index of seawater replacement is 1.33, the index of refraction of air is 1, which is why the angle of replacement is less than the incident angle, so the fish seems to be closer

In the opposite case, when the fish looked at the face of the man, the angle of greater reason why it seems to be further away

Explanation:

This exercise can be analyzed with the law of refraction that establishes that a ray of light when passing from one medium to another with a different index makes it deviate from its path,

      n₁ sin θ₁ = n₂ sin θ₂

where n₁ and n₂ are the refractive indices of the incident and refracted means and the angles are also for these two means.

In this case, the index of seawater replacement is 1.33, the index of refraction of air is 1, which is why the angle of replacement is less than the incident angle, so the fish seems to be closer

1 sin θ₁ = 1.33 sin θ₂

        θ₂ = sin⁻¹ ( 1/1.33 sin θ₁)

In the opposite case, when the fish looked at the face of the man, the angle of greater reason why it seems to be further away

4 0
2 years ago
Lizzie is pushing Alex on a scooter. Lizzie is pushing with 75 N of force to the left, and Alex is helping with 20 N to the left
nordsb [41]

Answer:

The net force on the scooter is 95 N to the left.

Explanation:

Lizzie is pushing with 75 N of force to the left, so the force is a vector with 75N of magnitude and to the left.

Alex is helping with 20 N to the left, so the force is a vector with 20 N magnitude and to the left.

When we add vectors, vectors that point in the same direction add up and vectors that point in opposite directions are subtracted.

Hence, the net force is equal to:

F=75 N + 20 N=95 N

As both forces point to the left, the net force is also to the left.

8 0
2 years ago
A roller coaster car drops a maximum vertical distance of 35.4 m. Determine the maximum speed of the car at the bottom of that d
marissa [1.9K]

Answer:

The maximum speed of the car at the bottom of that drop is 26.34 m/s.

Explanation:

Given that,

The maximum vertical distance covered by the roller coaster, h = 35.4 m

We need to find the maximum speed of the car at the bottom of that drop. It is a case of conservation of energy. The energy at bottom is equal to the energy at top such that :

mgh=\dfrac{1}{2}mv^2

v=\sqrt{2gh}

v=\sqrt{2\times 9.8\times 35.4}

v = 26.34 m/s

So, the maximum speed of the car at the bottom of that drop is 26.34 m/s. Hence, this is the required solution.

8 0
2 years ago
A fisherman is fishing from a bridge and is using a "44.0-N test line." In other words, the line will sustain a maximum force of
vitfil [10]

Answer:

a) 4.485 kg b) 3.94 kg

Explanation:

since the maximum tension the line can stand is 44 N and for question a the speed is constant (acceleration must be zero since the velocity or speed is not changing), F(tension) = mass * acceleration due to gravity (g) .

44 = m * 9.81m/s^2

m = 44/9.81 = 4.485kg

b) F(tension) = ma + mg ( where a is the acceleration of the body and g is the acceleration of the gravity)

44 = m (a +g)

44 = m (1.37 + 9.81)

44/11.18 = m

m = 3.94 kg

3 0
2 years ago
A solenoid with 3,000.0 turns is 70.0 cm long. If its self-inductance is 25.0 mH, what is its radius? (The value of μ0 is 4π x 1
nevsk [136]

Answer:

A. 2.2*10^-2m

Explanation:

Using

Area = length x L/ uo xN²

So A = 0.7m * 25 x 10^-3H /( 4π x10^-7*

3000²)

A = 17.5*10^-3/ 1.13*10^-5

= 15.5*10^-2m²

Area= π r ²

15.5E-2/3.142 = r²

2.2*10^2m

Explanation:

5 0
2 years ago
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