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IgorC [24]
2 years ago
13

The operations manager for a local bus company wants to decide whether he should purchase a small, medium, or large new bus for

his company. He estimates that the annual profits (in $000) will vary depending upon whether passenger demand is low, moderate, or high, as follows:
(a) If he uses the maximin criterion, which size bus will he decide to purchase?
(b) If he uses the minimax regret criterion, which size bus will he decide to purchase?
(c) If he feels the chances of low, moderate, and high demand are 30%, 30%, and 40% respectively, which size bus will he decide to purchase and what is the expected annual profit for this option?

Bus size Demand
Low Medium High
Small 50 60 70
Medium 40 80 90
Large 20 50 120
Business
1 answer:
ioda2 years ago
3 0

Answer:

a) the small bus

b) the medium or the larger bus

c) the small bus

Explanation:

a) under the maximin criterion the manager will want to maximise the minimum possible profit (pessimistic criterion) , thus the profits will be

Bus size Demand

Low Medium High

Small 50 60 70  → min profit = 50

Medium 40 80 90  → min profit = 40

Large 20 50 120 → min profit = 20

therefore the option with maximum minimum profit is the small size

b) under the maximin criterion the manager will want to minimise the maximum possible loss , thus the losses respect with the best profit option will be

Bus size Demand

Low Medium High  

Small 0 -20 -50  → max loss= -50

Medium -10 0 -30  → max loss = -30

Large -30 -30 0 → max loss = -30

therefore the option with minimum maximum loss is the medium or the large one

c) for the expected value of each option

small = 30/100*50 +30/100*60 +40/100*70 = 61

medium = 30/100*40 +30/100*80 +40/100*90 = 72

large = 30/100*20 +30/100*50 +40/100*120 = 69

then the small bus option is the better one, since it has the maximum expected profit

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2 years ago
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Sarah is planning a party at a party hall. The meal option is $50 per person and includes the hall for free. The hall-only optio
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Answer:

meal option  is cheaper with total cost = $2000 and hall only option is total cost  $2700

Explanation:

given data

The meal option = $50 per person.

Hall free = $ 0 per person

total guest = 40

hall-only option = $1,500

external caterer = $30 per person

solution

when we go for meal option than hall free so total cost will be as

total cost = total guest  × $50 per person

total cost = 40 × $50

total cost = $2000

and

when we go for hall only option than total cost will be

total cost = total guest   × external caterer charge + hall-only option

total cost =  40  × $30 + $1500

total cost =   $2700

so

meal option  is cheaper with total cost = $2000 and hall only option is total cost  $2700

4 0
2 years ago
1. How does Cobley connect the ideas of brands and force? What is his point about<br><br> brands?
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How does Cobley connect the ideas of brands and force? ... He connects them by saying that the more weight the brand has the more effort it takes to change or move that brand.

Explanation:

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2 years ago
A graphics reproduction firm has four units of equipment that are automatic but occasionally become inoperative because of the n
elena55 [62]

Answer:

(a) Average number of unit in line  = 0.256

(b) Average number of unit in operation= 3.209

(c) Average number of unit being service in operation = 0.535

Explanation:

Given Data:

Number of machine N = 4

Number of attendant (S) = 1

Service time (T)= 5 mins

Time required by the machine before servicing = 30 mins

Calculating the service factor (X) using the formula;

X = T/(T+U)

    = 5/(5+30)

    = 5/35

     = 0.1429

(a) Calculating the average number of unit in line (L) using the formula;

L = N* (1-F)

where, N = Number of unit

F = efficiency factor

L = average number of unit in line

Using the finite queuing table at X = 0.1429 and S = 1,

Efficiency factor = 0.936

Substituting, we have;

L = 4*(1-0.936)

   = 4* 0.064

   = 0.256

(c) Calculating the average number of unit being service in operation (H) using the formula;

H = N*F*X

   = 4 *0.936*0.1429

   = 0.535

(b) Calculating the average number of unit in operation using the formula;

Average number of unit in operation= Number of unit-down unit

But down unit = L+H

The formula becomes;

Average number of unit in operation= Number of unit-(L+H)

                                                             = 4 - (0.256+0.535)

                                                             = 4-0.791

                                                             = 3.209

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2 years ago
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