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zepelin [54]
2 years ago
8

A large crate sits on the floor of a warehouse. Paul and Bob apply constant horizontal forces to the crate. The force applied by

Paul has magnitude 48.0 N and direction 61.0∘ south of west. How much work does Paul’s force do during a displacement of the crate that is 12.0 m in the direction 22.0∘ east of north?

Physics
1 answer:
Tanya [424]2 years ago
7 0

Answer:

-570.4 J

Explanation:

Parameters given:

Force = 48N, 61° SW

Displacement = 12m, 22.0 NE

Work done is given by:

W = F*d*cosθ

To find θ:

θ = 61 + 90 + 22 = 172°

=> W = 48 * 12 * cos172

W = - 570.4 J

Hence, the work to be done is - 570.4J.

This value is negative because the applied force is opposite the direction of the displacement.

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John is carrying a shovelful of snow. The center of mass of the 3.00 kg of snow he is holding is 15.0 cm from the end of the sho
Andru [333]

Answer:

James is correct here as the force of hand pushing upwards is always more than the force of hand pushing down

Explanation:

Here we know that one hand is pushing up at some distance midway while other hand is balancing the weight by applying a force downwards

so here we can say

Upwards force = downwards Force + weight of snow

while if we find the other force which is acting downwards

then for that force we can say that net torque must be balanced

so here we have

F_{down} L_1 = W_{snow} L_2

so here we have

F_{down} = \frac{L_2}{L_1} (W_{snow})

so here we can say that upward force by which we push up is always more than the downwards force

8 0
2 years ago
7. A stick of length L and mass M is hanging at rest from its top edge from a ceiling hinged at that point so that it is free to
Lilit [14]

Answer:

The distance from the top of the stick would be 2l/3

Explanation:

Let the impulse 'FΔt' acts as a distance 'x' from the hinge 'H'. Assume no impulsive reaction is generated at 'H'. Let the angular velocity of the rod about 'H' just after the applied impulse be 'W'. Also consider that the center of percussion is the point on a bean attached to a pivot where a perpendicular impact will produce no reactive shock at the pivot.

Applying impulse momentum theorem for linear momentum.

FΔt = m(Wl/2), since velocity of center of mass of rod  = Wl/2

Similarly applying impulse momentum theorem per angular momentum about H

FΔt * x = I * W

Where FΔt * x represents the impulsive torque and I is the moment of inertia

F Δt.x = (ml² . W)/3

Substituting FΔt

M(Wl/2) * x = (ml². W)/3

1/x = 3/2l

x = 2l/3

8 0
2 years ago
1. One of the timing devices Galileo used was his pulse. Drop a rubber ball from a height of
Kamila [148]

The number of pulse beats elapsed before the rubber ball hits the ground can be obtained when you carry out the experiment yourself. However, the pulse beat method of timing used by Galileo is not reliable because it varies from time to time.

Galileo was interested in studying how objects fall. His discovery was that all objects had the same acceleration irrespective of their mass. This observation was in direct contrast to Aristotle's assertion that the velocity of objects is proportional to their mass.

However, he used his pulse beats as timer during the experiment. This method is unreliable because the pulse beats of a person changes depending on the person's state of mind. A stop clock could have been a more reliable timer than pulse beats.

Learn more: brainly.com/question/7201885

7 0
2 years ago
A thin electrical heating element provides a uniform heat flux qo" to the outer surface of a duct through which air flows. The d
Ivanshal [37]

Answer:

a)q= 2800 W/m²

b)To=59.4°C

Explanation:

Given that

L = 10 mm

K= 20 W/m·K

T=30°C

h= 100 W/m²K

Ti=58°C

a)

Heat flux q

q= h ΔT

q= 100 x (58 - 30 )

q= 2800 W/m²

b)

As we know that heat transfer by Fourier law given as

Q= K A ΔT/L

Lets take outer temperature is To

So by  Fourier law

To= Ti + qL/K

Now by putting the values

To= Ti + qL/K

To= 58 + 2800 \times \dfrac{ 0.01}{20}

To=59.4°C

5 0
2 years ago
Duff is a breakdancer whose signature move is spinning around on his head while his body is upside down. Which axis is Duff rota
padilas [110]

Answer:

vertical axis

Explanation:

Duff is a breakdancer whose signature move is spinning around on his head while his body is upside down. It means that the center of axis lies at the center of head. it means that Duff is rotating at vertical axis.

Hence, the correct option is (b) "vertical axis"

4 0
2 years ago
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