Answer:
t= 12.9 years
Step-by-step explanation:
Value after t years = initial value ( 1 - r )^t
Where,
Value after t years= $5000
Initial value = $22,400
r= depreciation rate = 11%
t= length of time (years)
Value after t years = initial value ( 1 - r )^t
5000 = 22,400 ( 1 - 0.11)^t
5000 = 22,400(0.89)^t
Divide both sides by 22,400
(0.89)^t = 5000 / 22,400
(0.89)^t = 0.2232
Take the log of both sides
t log 0.89 = log 0.2232
t= log 0.2232 / log 0.89
= -0.6513 / -0.0506
= 12.87
t= 12.9 years
12, Carmen buys 12 roses
I got this by multiplying 4x3=12
First lets write down our starting conditions:
we have 22 gallons and it has 16% of ammonia
16% of 22 gallons is
A = 16/100*22 = 3,52 gallons
Now since only watter is evaporating that means that in second scenario after some watter evaporated there is still 3,52 gallons of ammonia. But now those 3,52 gallons of ammonia represent 24% of total mixture. So now we go other way.
24 % is 3,52 gallons
100% is x gallons
x = 100/24*3,52 = 14.667 gallons
That means that he has to evaporate
22 - 14.6667 = 7,333 gallons of water.
Answer:
The standard deviation on the critical path = 0.834
Step-by-step explanation:
Variance of activity A (
) = 0.33
Variance of activity B (
) = 0.67
Variance of activity C (
) = 0.33
Variance of activity D (
) = 0.17
Thus the standard deviation on the critical path (
) =
+
+
+ 
=
+
+
+
= 0.6956
= 0.834
The standard deviation on the critical path = 0.834
Answer:
-33.5
Step-by-step explanation:
So this is a dot products vector problem, so the i and j represent x and y or horizontal and vertical components. So you multiple 3i and -0.5i and then separately multiply 8j and -4j. You get -1.5 and -32. Now all you have to do is add them and you get -33.5.
Basically in short:
1. Multiply the “i’s”.
2. Multiply the “j’s”.
3. Add the two products together.
HOPE THIS HELPS !! :-)