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Grace [21]
2 years ago
6

Four distinguishable particles move freely in a room divided into octants (there are no actual partitions). Let the basic states

be given by specifying the octant in which each particle is located. How many basic states are there?
Physics
1 answer:
mafiozo [28]2 years ago
8 0

Answer:

Explanation:

Since the door that leads to the room is opened, this gives room for particles to move into the next identical room and divided into octants. Now the amount of space that can be occupied becomes double, the number of basic states has increased by 404916

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450 meters, straight ahead is the answer.
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a 2 meter tall astronaut standing on mars drops her glasses from her nose. how long will the astronaut have before he hits the g
lorasvet [3.4K]
Here,
Height (S) = 2m
Gravity on mars (g) = 3.7m/s^2
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2 = 0 * t + 1/2*3.7*t^2
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2 years ago
5. A nail contains trillions of electrons. Given that electrons repel from each other, why do they not then fly out of the nail?
diamong [38]

Answer:

Nails are made of iron. Iron consists of 26 protons and 26 electrons. protons are positively charged and electrons are negatively charged, so this force of attraction keeps the electrons together.

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4 0
2 years ago
Two weights are connected by a very light cord that passes over an 80.0Nfrictionless pulley of radius 0.300m. The pulley is a so
Citrus2011 [14]

Answer:

The force does the ceiling exert on the hook is 269.59 N

Explanation:

Applying the second Newton law:

F = m*a

From the attached diagram, the net force in object 1 is:

m_{1} a=T_{1} -W_{1}

In object 2:

m_{2} a=W_{2} -T_{2}

Adding the two equations:

m_{2} a+m_{1} a=T_{1} -W_{1} +W_{2} -T_{2} \\m_{1} =\frac{W_{1} }{g} \\m_{2} =\frac{W_{2} }{g} \\Replacing\\T_{2}-T_{1}=W_{2}   -W_{1} -(\frac{W_{1} }{g} +\frac{W_{2} }{g} )a  (eq. 1)

The torque:

\tau =I\alpha

Where

I = moment of inertia

α = angular acceleration

If the linear acceleration is

a=r\alpha \\\alpha =\frac{a}{r} \\I=\frac{1}{2} mr^{2} \\\tau =\frac{mra}{2}

Torque due the tension is equal:

\tau =r(T_{2} -T_{1} )

Substituting torque, mass, in equation 1, the expression respect the acceleration is:

a=\frac{g*(W_{2}-W_{1})}{W_{1}+W_{2} +\frac{W}{2} }

Where

W₁ = 75 N

W₂ = 125 N

W = 80 N

a=\frac{9.8*(125-75)}{75+125+\frac{80}{2} } =2.04m/s^{2}

The net force is:

F_{n} =F-W-T_{1} -T_{2}\\0=F-W-W_{1} (\frac{a}{g} +1)-W_{2} (1-\frac{a}{g})\\F=W+W_{1} +W_{2} +\frac{a}{g} (W_{1} -W_{2} )\\F=80+75+125+\frac{2.04}{9.8} (75-125)\\F=269.59N

4 0
2 years ago
A historical society is testing an old cannon. They
sveta [45]

Answer:

26.2 m/s

Explanation:

We can find the speed of the cannonball just by analyzing its vertical motion. In fact, the initial vertical velocity is

u_y = u sin \theta (1)

where u is the initial speed and \theta = 45.0^{\circ} is the angle of projection.

We can therefore use the following suvat equation for the vertical motion of the ball:

v_y = u_y + at

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t=\frac{3.78}{2}=1.89 s

And at the maximum height, the vertical velocity is zero:

v_y=0

Substituting these values, we find the initial vertical velocity:

u_y = v_y - at = 0-(-9.8)(1.89)=18.5 m/s

And using eq.(1) we now find the initial speed:

u=\frac{u_y}{sin \theta}=\frac{18.5}{sin 45.0^{\circ}}=26.2 m/s

4 0
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