Question

During a practice shot put throw, the 7.9-kg shot left world champion C. J. Hunter's hand at speed 16 m/s. While making the throw, his hand pushed the shot a distance of 1.7 m. Assume the acceleration was constant during the throw.
A) Determine the acceleration of the shot.B) Determine the time it takes to accelerate the shot.C) Determine the horizontal component of the force exerted on the shot by hand.

Answer 1

Answer:

Explanation:

u = 0

v = 16 m /s

s = 1.7 m

v² = u² + 3 a s

16² = 0 + 2 x a x 1.7

a = 16² / 2 x 1.7

= 75 . 3 m /s²

B )

v = 16 m /s

u = 0

a = 75.3 m /s²

v = u + at

16 = 0 + 75.3 t

t = 16 / 75.3

=  0.212 s

C )

Force = mass x acceleration

= 7.9 x 75.3

= 594.87 N