Question

Calculate the velocity of electrons that form the same pattern as 450-nm light when passed through a double slit. The mass of an electron is 9.11 \times 10^{-31}~\text{kg}9.11×10 ​−31 ​​ kg.

Answer 1

Answer:

The velocity of electrons is 1617.27 m/s.

Explanation:

Given that,

Wavelength of light, $\lambda=450\ nm=450\times 10^{-9}\ m$

Mass of an electron, $m=9.11\times 10^{-31}\ kg$

We need to find the velocity of electrons. It can be given by using De-Broglie wavelength such that :

$\lambda=\dfrac{h}{mv}\\\\v=\dfrac{h}{m\lambda}\\\\v=\dfrac{6.63\times 10^{-34}}{9.11\times 10^{-31}\times 450\times 10^{-9}}\\\\v=1617.27\ m/s$

So, the velocity of electrons is 1617.27 m/s. Hence, this is the required solution.