<h3>
Answer:</h3>
TRUE- The surface tension of CH3Br is greater than the surface tension of CH3Cl.
FALSE-Water forms spherical drops on wax because the surface tension of water is greater than the adhesive forces between wax and water.
<h3>
Explanation:</h3>
- The statement that, the surface tension of CH3Br is greater than the surface tension of CH3Cl is true.
- This is because of the fact that CH₃Br has more molar mass compared to CH₃Cl. Additionally, CH₃Br has greater dispersion forces and is more polarizable thus having greater surface tension compared to CH₃Cl.
- The statement that "Water forms spherical drops on wax because the surface tension of water is greater than the adhesive forces between wax and water" is FALSE.
- We would correct it by saying, Water forms spherical drops on wax because the cohesive force of water is greater than the adhesive forces between wax and water.
- Cohesive forces are forces of attraction between molecules or particles of the same type while adhesive forces is a force of attraction between molecules of different type.
A skeletal formula is usually used for organic compounds
The outer electron of atom B has moved to a higher energy state.<span>B - 1s2, 2s2, 2p6, 5s1 </span>
Answer:
A source of electricity, a wire coil, and an iron core
Explanation:
An electromagnet has three critical components:
1. A source of electricity
This is often a battery.
It generates the electric current that produces the magnetic field.
2. A wire coil
The wire carries the electric current.
Stacking the wire into loops makes a stronger magnetic field.
The more loops in the coil, the stronger the field.
3. An iron core
An iron core greatly increases the strength of the magnetic field within it and at its ends.
Answer:
pH=10.97
Explanation:
the solution of methyl amine with methylammonium chloride will make a buffer solution.
The pH of buffer solution can be obtained using Henderson Hassalbalch's equation, which is:
![pOH=pKb+log\frac{[salt]}{[base]}](https://tex.z-dn.net/?f=pOH%3DpKb%2Blog%5Cfrac%7B%5Bsalt%5D%7D%7B%5Bbase%5D%7D)
pH = 14- pOH
Let us calculate pOH
[Salt] = [methylammonium chloride] = 0.10 M (initial)
After adding base
![[salt] = \frac{molarityXvolume}{finalvolume}=\frac{0.1X20}{(20+50)}= 0.0286M](https://tex.z-dn.net/?f=%5Bsalt%5D%20%3D%20%5Cfrac%7BmolarityXvolume%7D%7Bfinalvolume%7D%3D%5Cfrac%7B0.1X20%7D%7B%2820%2B50%29%7D%3D%200.0286M)
[base] = [Methylamine]=0.10
After mixing with salt
![[base]= \frac{molarityXvolume}{finalvolume}=\frac{0.1X50}{(20+50)}= 0.0714M](https://tex.z-dn.net/?f=%5Bbase%5D%3D%20%5Cfrac%7BmolarityXvolume%7D%7Bfinalvolume%7D%3D%5Cfrac%7B0.1X50%7D%7B%2820%2B50%29%7D%3D%200.0714M)
pKb= -log[Kb]= 3.43
Putting values
pOH = ![3.43+log(\frac{[0.0286]}{0.0714}](https://tex.z-dn.net/?f=3.43%2Blog%28%5Cfrac%7B%5B0.0286%5D%7D%7B0.0714%7D)
