Answer:
1,269 N
Explanation:
A space station with a radius of 120 m rotates once every 70 s to create artificial gravity. If the astronaut has an earth weigh
1 answer:
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Answer:
The simplified expression is
Explanation:
From the question we are told that
So simplifying we have
Thus the simplified formula is
Answer:
A) x _electron = 0.66 10² m , B) x _Eart = 1.13 10² m , C) d_sphere = 1.37 10⁻² mm
Explanation:
A) Let's use a ball for the nucleus, the electron is at a farther distance the sphere for the electron must be at a distance of
Let's use proportions rule
x_ electron = 0.529 10⁻¹⁰ /1.2 10⁻¹⁵ 1.5
x _electron = 0.66 10⁵ mm = 0.66 10² m
B) the radii of the Earth and the sun are
= 6.37 10⁶ m
tex]R_{Sum}[/tex] = 6.96 10⁸ m
Distance = 1.5 10¹¹ m
x_Earth = 1.5 10¹¹ / 6.96 10⁸ 1.5
x _Eart = 1.13 10² m
C) The radius of a sphere that represents the earth, if the sphere that represents the sun is 1.5 mm, let's use another rule of proportions
d_sphere = 1.5 / 6.96 10⁸ 6.37 10⁶
d_sphere = 1.37 10⁻² mm
Answer:
The magnitude of the force on the dipole due to the charge Q =
The magnitude of the torque on the dipole =
Explanation:
Given that a point charge Q is held at a distance r from the center of a dipole that consists of two charges ±q, separated by a distance s and the charge Q is located in the plane that bisects the dipole.
The magnitude of the electric field that the dipole exerts at the position where the charge Q is held is given by
<em>where</em>,
k is the Coulomb's constant, having value =
is the electrical permittivity of free space.
Also, r>>s, therefore,
The magnitude of the electric force F on a charge q placed at a point and the magnitude of the electric field E at that point are related as
Therefore, the electric force on the charge Q due to the dipole is given by
According to Newton's third law of motion, the magnitude of the force exerted by the dipole on the charge Q is same as the magnitude of the force exerted by the charge on the dipole.
Thus, the magnitude of the force on the dipole due to the charge Q =
The magnitude of the torque on the dipole is given by
Since the charge Q is placed in the plane that bisects the dipole, therefore, .