Question

A local race for charity has taken place since 1993. Using the actual speeds of the winners from 1993 through 1998, mathematicians obtained the formula , in which x represents the number of years after 1993 and y represents the winning speed in miles per hour. In what year is the winning speed predicted to be 7.4 mph?

Answer 1

Answer:

Here is a similar question attached with.

Option (b) that is 2005 is the right choice.

Step-by-step explanation:

Given:

An equation in slope intercept form.

$y=0.18(x) + 5$

Where $x$ = number of years

Comparing from the standard slope intercept form.

$y=m(x) + b$

y-intercept value $(b) = 5$

According to the question the predicted winning speed $(y) = 7.16$ mph

Plugging the value of $y$ in slope intercept form, we will calculate the $x$ (number of years) and then we will add this with $1993$ .

⇒ $y=0.18(x)+5$

⇒ $7.16=0.18(x)+5$

⇒ $7.16-5=0.18(x)$

⇒ $2.16=0.18(x)$

⇒ $\frac{2.16}{0.18} =x$

⇒ $12=x$

Finally the year would be $1993+12=2005$  

So in year 2005 the winning speed is predicted to be 7.16 mph.