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Elina [12.6K]
2 years ago
3

A student with a mass of 80.0 kg runs up three flights of stairs in 12.0 sec. The student has gone a vertical distance of 8.0 m.

Determine the amount of work done by the student to elevate his body to this height. Determine the power consumed by the student. Assume that his speed is constant.
Physics
1 answer:
kolbaska11 [484]2 years ago
3 0
<h2>The amount of work done by the student to elevate his body to this height is 6278.4 J</h2><h2>Power is 523.2 Watts</h2>

Explanation:

Work = Force x Displacement

Force = Weight of student

Weight = Mass x Acceleration due to gravity

Mass, m = 80 kg

Acceleration due to gravity, g = 9.81 m/s²

Weight = 80 x 9.81 = 784.8 N

Displacement = 8 m

Work = 784.8 x 8 = 6278.4 J

The amount of work done by the student to elevate his body to this height is 6278.4 J

Power is the ratio of work to time taken

         P=\frac{W}{t}\\\\P=\frac{6278.4}{12}\\\\P=523.2W

Power is 523.2 Watts

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storchak [24]

Answer: There will be 75258 nuclei left at 6 pm.

Explanation:

a) half-life of the radioactive substance:

Half life is the amount of time taken by a radioactive material to decay to half of its original value.

t_{\frac{1}{2}}=\frac{0.69}{k}

k=\frac{0.69}{t_{\frac{1}{2}}}=\frac{0.693}{2hours}=0.346hours^{-1}

b) Expression for rate law for first order kinetics is given by:

A=A_0e^{-kt}

where,

k = rate constant  

t = time for decomposition = 6 hours ( from 12 noon to 6 pm)

A = activity at time t = ?

A_0 = initial activity  = 600, 000

A=600000\times e^{-0.346\times 6}

A=75258

Thus there will be 75258 nuclei left at 6 pm.

7 0
2 years ago
A heavy frog and a light frog jump straight up into the air. They push off in such away that they both have the same kinetic ene
Ilia_Sergeevich [38]

Answer:

The lighter frog goes higher than the heavier frog.

The lighter frog is moving faster than the heavier frog

Explanation:

If both frogs have the same kinetic energy when they leave the ground, the following equality applies:

K(light) = K(heavy) = \frac{1}{2} *ml*vol^{2} = \frac{1}{2}*mh*voh^{2}

Now, if the only force acting on the frogs is gravity, when they reach to the maximum height, we can apply the following kinematic equation:

vf^{2} -vo^{2} = 2*a*hmax = vf^{2} -vo^{2} = 2*(-g)*hmax

When h= hmax, the object comes momentarily to an stop, so vf =0

Solving for hmax:

hmax =\frac{vo^{2} }{2*g}

As the lighter frog, in order to have the same kinetic energy than the heavier one, has a greater initial velocity, it will go higher than the other.

As a consequence of both having the same kinetic energy, the lighter frog will be moving faster than the heavier frog.

5 0
2 years ago
Suppose you wanted to hold up an electron against the force of gravity by the attraction of a fixed proton some distance above i
SCORPION-xisa [38]

Answer:

The value is  r =  5.077 \  m

Explanation:

From the question we are told that

   The  Coulomb constant is  k =  9.0 *10^{9} \  N\cdot  m^2  /C^2

   The  charge on the electron/proton  is  e =  1.6*10^{-19} \  C

    The  mass of proton m_{proton} =  1.67*10^{-27} \  kg

    The  mass of  electron is  m_{electron } =  9.11 *10^{-31} \ kg

Generally for the electron to be held up by the force gravity

   Then    

       Electric force on the electron  =  The  gravitational Force

i.e  

            m_{electron} *  g  = \frac{ k *  e^2  }{r^2 }

         \frac{9*10^9 *  (1.60 *10^{-19})^2  }{r^2 }  =     9.11 *10^{-31 }  *  9.81

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         r =  5.077  \  m

7 0
2 years ago
Arwan finds a piece of quartz while hiking in the mountains. When he returns to school, he takes it to his science teacher. She
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it's 303.4 cm3. i just took the test

8 0
2 years ago
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s344n2d4d5 [400]

Answer:

<u>The flux decreases because the angle between B⃗ and the coil's axis changes.</u>

<u />

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The flux through the coil is given by a dot product, between the magnetic field and the vector representing the area of the coil.

\Phi = \vec{B}\cdot \vec{S} = BScos(\theta)

The latter vector has direction perpendicular to the plane in which the area of the coil is, and magnitude equal to the area of the coil. As in the attached image, the vector S is the vector respresenting the area of the coil.

Therefore, the flux will be maximum when the vector S is in the same direction as B, and will be zero when they are perpendicular.

Now, if <em>the coil is rotated so that the magnetic field is in the plane of the coil </em>then, the vectors S and B are perpendicualr, and there will not be net magnetic flux, that is, the flux will decrease.

3 0
2 years ago
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