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nalin [4]
2 years ago
3

Find the median path loss under the Hata model assuming fc = 900 MHz, ht = 20m, hr = 5 m and d = 100m for a large urban city, a

small urban city, a suburb, and a rural area. Explain qualitatively the path loss differences for these 4 environments.

Engineering
1 answer:
pav-90 [236]2 years ago
7 0

Answer:

The solution and complete explanation for the above question and mentioned conditions is given below in the attached document.i hope my explanation will help you in understanding this particular question.

Explanation:

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Which of the following is NOT a characteristic of hazardous waste
lbvjy [14]

Answer:

A RCRA characteristic hazardous waste is a solid waste that exhibits at least one of four characteristics defined in 40 CFR Part 261 subpart C — ignitability (D001), corrosivity (D002), reactivity (D003), and toxicity (D004 - D043). combustible, or have a flash point less than 60 °C (140 °F).

8 0
2 years ago
Water flows through two smooth pipes with the same diameter and length as shown below. ipe is twice that through the first-pipe.
Alisiya [41]

Answer:

The right answer is (d)

Explanation:

The pressure drop in smooth pipes with laminar flow is determined by the resistance of the fluid to flow, which is controlled by Reynolds's number. At higher Re, higher drop. But in this case, we have no information about the speed of the fluid in each pipe, and the ipe is not related to that speed. therefore we don´t have the information to say that any of the other options are the right ones

3 0
2 years ago
Plot the data as impact energy versus temperature: (b) Determine a ductile-to-brittle transition temperature as the temperature
Shkiper50 [21]

Question:

The following tabulated data were gathered from a series of Charpy impact tests on a commercial low-carbon steel alloy.

Temperature(∘C)50403020100-10-20-30-40Impact energy (J)76767158382314951.5

(a) Plot the data as impact energy versus temperature.

(b) Determine a ductile-to-brittle transition temperature as the temperature corresponding to the average of the maximum and minimum impact energies.

(c) Determine a ductile-to-brittle transition temperature as the temperature at which the impact energy is 20 J.

Answer:

a)  see the attached graph

b) max E = 76 and Min E =1.53 average = 77.5/2 = 38.75 J

this corresponds to about 10° C

c ) at E = 20 J temperature is about -2°C

8 0
2 years ago
Read 2 more answers
The Driver of a vehicle on a level road determined that she could increase her speed from rest to 50 mi/h in 12.8 sec and from r
Ket [755]

Answer:

maximum acceleration is  1.746 m/s²

Explanation:

given data

\frac{du}{dt} = (α) - (β) ×(u(t))  

speed = rest to 50 mi/h = 22.352 m/s

time =  12.8 sec

speed = rest to 65 mi/h = 29.05 m/s

time =  19.8 sec

solution

we get here maximum acceleration of vehicle that is

maximum acceleration = \frac{\frac{du}{dt} }{t}

maximum acceleration = \frac{v1-V2}{t}    ...............1

put here value

maximum acceleration = \frac{22.352-0}{12.8}

maximum acceleration = 1.746 m/s²

and for another vehicle

maximum acceleration = \frac{29.05-0}{19.8}

maximum acceleration = 1.46 m/s²

so here maximum acceleration is  1.746 m/s²

6 0
2 years ago
For a two-source network, if current produced by one source is in one direction, while the current produced by the other source
Bezzdna [24]

Answer:

c. The sum of the two and the direction of  either.

Explanation:

If both sources are linear, we can apply the superposition theorem, which in this case, states simply that the resulting current is just the algebraic sum of both currents.

This is due to any of them, is independent from the other, so we can calculate her influence without any other source present.

Assuming that both sources are ideal (no shunt resistances) , we can apply superposition, removing all sources but one each time, just replacing the sources by an open circuit.

Let's suppose that we have a 5A source flowing to the rigth, and a 3A source in the opposite direction.

Applying superposition, we have:

I₁ = 5A (the another source is removed)

I₂ = -3A (The minus sign indicates that is flowing in the opposite direction, 5A source is removed)

I = I₁ + I₂ = 5A + (-3A) = 2 A

As it can be seen , the resulting current is the sum (algebraic) of both current sources, and has the direction of either of the sources, depending on the absolute value of the current sources.

(If the directions of I₁ and I₂ were inverted, with the same absolute values, the direction would be the opposite).

We could have arrived to the same result applying KCL.

6 0
2 years ago
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