Answer:
c. the arcs represent one-way streets.
Explanation:
Answer:
FileOutputStream out = new FileOutputStream("ObjectData.dat");
ObjectOutputStream ostream = new ObjectOutputStream(out);
ostream.writeObject(r);
Explanation:
For object serialization, we can use the writeObject method of java.io.ObjectOutputStream class.
The complete code fragment is as follows:
import java.io.*;
class Demo{
public static void main(String args[]){
try{
r = <Reference to Object to be serialized> ;
FileOutputStream out = new FileOutputStream("ObjectData.dat");
ObjectOutputStream ostream = new ObjectOutputStream(out);
ostream.writeObject(r);
ostream.close();
} catch(Exception e){
e.printStackTrace();
}
}
}
Answer:



So then the value of the maximum I/O wait that can be tolerated is 0.720 or 72 %
Explanation:
Previous concepts
Input/output operations per second (IOPS, pronounced eye-ops) "is an input/output performance measurement used to characterize computer storage devices like hard disk drives (HDD)"
Solution to the problem
For this case since we have 4GB, but 512 MB are destinated to the operating system, we can begin finding the available RAM like this:
Available = 4096 MB - 512 MB = 3584 MB
Now we can find the maximum simultaneous process than can use with this:

And then we can find the maximum wait I/O that can be tolerated with the following formula:

The expeonent for p = 14 since we got 14 simultaneous processes, and the rate for this case would be 99% or 0.99, if we solve for p we got:



So then the value of the maximum I/O wait that can be tolerated is 0.720 or 72 %
Answer:
The solution is written using Python as it has a simple syntax.
- def getHighScores(gameScores, minScore):
- meetsThreshold = []
- for score in gameScores:
- if(score > minScore):
- meetsThreshold.append(score)
- return meetsThreshold
- gameScores = [2, 5, 7, 6, 1, 9, 1]
- minScore = 5
- highScores = getHighScores(gameScores, minScore)
- print(highScores)
Explanation:
Line 1-8
- Create a function and name it as <em>getHighScores</em> which accepts two values, <em>gameScores</em> and <em>minScore</em>. (Line 1)
- Create an empty list/array and assign it to variable <em>meetsThreshold</em>. (Line 2)
- Create a for loop to iterate through each of the score in the <em>gameScores</em> (Line 4)
- Set a condition if the current score is bigger than the <em>minScore</em>, add the score into the <em>meetsThreshold</em> list (Line 5-6)
- Return <em>meetsThreshold</em> list as the output
Line 11-12
- create a random list of <em>gameScores</em> (Line 11)
- Set the minimum score to 5 (Line 12)
Line 13-14
- Call the function <em>getHighScores()</em> and pass the<em> gameScores</em> and <em>minScore </em>as the arguments. The codes within the function <em>getHighScores()</em> will run and return the <em>meetsThreshold </em>list and assign it to <em>highScores.</em> (Line 13)
- Display <em>highScores</em> using built-in function print().
Answer:
The answer is A.Absolute reference.
Explanation:
Absolute reference is a cell reference whose location remains constant when the formula is copied.