<u>Answer:</u> The energy of the complex is
<u>Explanation:</u>
To calculate the energy of the complex, we use the equation given by Planck which is:
where,
= Wavelength of the complex =
(Conversion factor:
)
h = Planck's constant =
c = speed of light =
= Avogadro's number =
= energy of the complex
Putting values in above equation, we get:
Conversion factor used: 1 kJ = 1000 J
Hence, the energy of the complex is
Answer:
1.18 V
Explanation:
The given cell is:
Half reactions for the given cell follows:
Oxidation half reaction:
Reduction half reaction:
Multiply Oxidation half reaction by 2 and Reduction half reaction by 3
Net reaction:
Oxidation reaction occurs at anode and reduction reaction occurs at cathode.
To calculate the of the reaction, we use the equation:
Putting values in above equation, we get:
To calculate the EMF of the cell, we use the Nernst equation, which is:
where,
= electrode potential of the cell = ?V
= standard electrode potential of the cell = +1.21 V
n = number of electrons exchanged = 6
Putting values in above equation, we get:
Answer:
Upper F subscript 2 (g) plus upper C a (s) right arrow with delta above upper C a upper F subscript 2 (s).
Explanation:
This is a chemical reaction problem.
In expressing any chemical reaction, we need to understand that there are reactants and products.
Using the statement of this problem, we can deduce that;
Reactants are Fluorine gas and Calcium metal
Product is Calcium Fluoride
Note: A metal is a solid(s) and powder is a solid(s). A gas is denoted as (g). They depict the state of the species reacting.
F₂ + Ca
→ CaF₂
We can see that equal number of atoms are on both sides of the expression.