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Svetradugi [14.3K]
2 years ago
4

A chemistry student needs of heptane for an experiment. He has available of a w/w solution of heptane in chloroform. Calculate t

he mass of solution the student should use. If there's not enough solution, press the "No solution" button. Round your answer to significant digits.
Chemistry
1 answer:
tensa zangetsu [6.8K]2 years ago
6 0

The question is incomplete, here is the complete question:

A chemistry student needs 65.0 g heptane for an experiment. He has available 20.0 g of a 38.1% w/w solution of heptane in chloroform.

Calculate the mass of solution the student should use. If there's not enough solution, press the "No solution" button.  Round your answer to 3 significant digits.

<u>Answer:</u> The solution is not enough, "No Solution"

<u>Explanation:</u>

We are given:

Mass of solution needed = 20.0 g

Mass of heptane given = 65.0 g

38.1 % (w/w) solution of heptane

This means that 38.1 grams of heptane is present in 100 grams of solution

To calculate the amount of solution needed, we apply unitary method:

If 38.1 grams of heptane is present in 100 g of solution

So, 65.0 grams of heptane will be present in = \frac{100}{38.1}\times 65.0=170.6g of solution

As, the given amount of solution is less than the required solution. So, there is not enough solution

Hence, the solution is not enough, "No Solution"

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kati45 [8]

Answer:

a. The original temperature of the gas is 2743K.

b. 20atm.

Explanation:

a. As a result of the gas laws, you can know that the temperature is inversely proportional to moles of a gas when pressure and volume remains constant. The equation could be:

T₁n₁ = T₂n₂

<em>Where T is absolute temperature and n amount of gas at 1, initial state and 2, final states.</em>

<em />

<em>Replacing with values of the problem:</em>

T₁n₁ = T₂n₂

X*7.1g = (X+300)*6.4g

7.1X = 6.4X + 1920

0.7X = 1920

X = 2743K

<h3>The original temperature of the gas is 2743K</h3><h3 />

b. Using general gas law:

PV = nRT

<em>Where P is pressure (Our unknown)</em>

<em>V is volume = 2.24L</em>

<em>n are moles of gas (7.1g / 35.45g/mol = 0.20 moles)</em>

R is gas constant = 0.082atmL/molK

And T is absolute temperature (2743K)

P*2.24L = 0.20mol*0.082atmL/molK*2743K

<h3>P = 20atm</h3>

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7 0
2 years ago
The nucleus of an atom is dense and positively charged. What was observed when positively charged particles were radiated onto a
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<span>According to my knowledge, I feel the answer is -
Particles that struck the center of the atom were repelled.

Hope this helps!
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8 0
2 years ago
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The boiling point of water is 100°C and the difference is when will the water start boiling.

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Suppose, in an experiment to determine the amount of sodium hypochlorite in bleach, you titrated a 26.34 mL sample of 0.0100 M K
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0.1 M

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Answer:

As you haven't explained what measurements you took before solving this problem, I will explain the general procedure to evaluate the efficiency of a kettle. I hope it helps you. I´ll send an attachement file with the full answer, since I couldn't write it here.

I assume that the material that is going to be heated in the kettle is water.

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3- Divide Q by the time it took to bring the water to boiling so you can have the power it consumed.

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